Server Side Programming Articles - Page 1373 of 2650

Given a sorted doubly linked list containing integer values. The goal is to find triplets whose product is equal to the given value x. If input linked list is 3−4−1−2 and x is 6 then count will be 1 (triplet (3, 1, 2) )For ExampleInputlinked list: [ 3−4−13−5−10−10−0 ] x=20OutputCount of triplets in a sorted doubly linked list whose product is equal to a given value x are: 2ExplanationTriplets will be: ( 3, 4, 13 ) and ( 10, 10, 0 )Inputlinked list: [ 4−3−1−5−2−4−2 ] x=8OutputCount of triplets in a sorted doubly linked list whose product is equal to ... Read More

Given a sorted doubly linked list containing integer values. The goal is to find triplets whose product is equal to the given value x. If input linked list is 3−4−1−2 and x is 6 then count will be 1 (triplet (3, 1, 2))For ExampleInputlinked list: [ 200−4−16−5−10−10−2 ] x=200OutputCount of triplets in a sorted doubly linked list whose product is equal to a given value x are: 3ExplanationTriplets will be: (4, 5, 10), (4, 5, 10) and (10, 10, 2)Inputlinked list: [ 4−3−1−5−2−4−2] x=12OutputCount of triplets in a sorted doubly linked list whose product is equal to a given value ... Read More

Given an array arr[] containing integer elements and an integer num. The goal is to find the average of each element arr[i] and num and print the count of the number of times that average appeared in the original array.If array arr[] is [ 5, 2, 3 ] and num is 2. Averages will be [ 3, 2, 2 ] occurrences in arr[] is [ 1, 1, 1 ]For ExampleInputarr[] = { 1, 6, 4, 3, 6, 4 } num=2Output1 2 1 0 2 1Count of occurrences of the average of array elements with a given number are − 5ExplanationThe ... Read More

Given a string str, a character and a positive integer N. The string str is repeated indefinitely. The goal is to find the count of occurrences of character in str in first N characters of repetitions.If str is “abac”, character is ch=‘b’ and N is 10.In first 10 characters of “abacabacabacabac…….” b occurs twice.Note − Take str and character ch within the same case.Let us understand with examples.For ExampleInputstr = "TPTTTT" ch = 'T' n = 12OutputCount of occurrences of a character in a repeated string are: 10ExplanationThe number of ‘T’ in str is 5. Length of str is 6. ... Read More

The default residual plot can be created by using the model object name in base R but that is not very attractive. To create a residual plot with better looking aesthetics, we can use resid_panel function of ggResidpanel package. It is created in the same way as the residual plot in base R, also it results in all the relevant graph in one window.ExampleConsider the below data frame −Live Demo> x y df dfOutputx y 1 0.48508894 0.217379409 2 0.75113573 -0.657179470 3 -0.13075185 -0.549613217 4 -0.26867557 1.156736294 5 0.40407850 0.640387394 6 -0.23816272 -0.807847198 7 -0.57278583 0.600249694 8 -0.78222676 -0.711133218 9 ... Read More

If we have two string vectors, each containing more than two values then it becomes a little difficult to create the combinations for each string value in those two vectors. For this purpose, we can make use of do.call function paste0 and expand.grid as shown in the below examples.ExampleLive Demo> x1 y1 do.call(paste0, expand.grid(x1, y1))Output[1] "AK" "BK" "CK" "DK" "EK" "FK" "GK" "HK" "IK" "JK" "AL" "BL" "CL" "DL" "EL" [16] "FL" "GL" "HL" "IL" "JL" "AM" "BM" "CM" "DM" "EM" "FM" "GM" "HM" "IM" "JM" [31] "AN" "BN" "CN" "DN" "EN" "FN" "GN" "HN" "IN" "JN" "AO" "BO" "CO" ... Read More

To get the top values in an R data frame, we can use the head function and if we want the values in decreasing order then sort function will be required. Therefore, we need to use the combination of head and sort function to find the top values in decreasing order. For example, if we have a data frame df that contains a column x then we can find top 20 values of x in decreasing order by using head(sort(df$x, decreasing=TRUE), n=20).ExampleConsider the CO2 data frame in base R −Live Demo> str(CO2)OutputClasses ‘nfnGroupedData’, ‘nfGroupedData’, ‘groupedData’ and 'data.frame': 84 obs. of ... Read More

Sometimes we need the multiplication of two columns and create a new column so that the multiplication can be used further for analysis. For example, to calculate BMI we need mass and height and the height is squared, therefore, we would be needing the square of height. For this purpose, we can either multiply height with height or simply take the square both the ways work. Hence, if only have height column in an R data frame then we can multiply it with itself.ExampleConsider the below data frame −Live Demo> set.seed(957) > x y z df dfOutputx y z 1 ... Read More

In R, by default the whisker lines are as wide as the box of the boxplot but it would be great if we reduce that width or increase it because it will get attention of the viewer in that way. This can be done by using the width argument inside the stat_boxplot function of ggplot2 package. Check out the below example to understand how it works.ExampleConsider the below data frame −ExampleLive Demo> x y df dfOutputx y 1 B 5 2 B 4 3 A 6 4 A 9 5 B 2 6 B 4 7 B 6 8 B ... Read More

To find the sum of division if zero exists in the vectors, we need to assign NA to zeros in both the vectors and then use the sum function with na.rm set to TRUE. For example, if we have two vectors x and y that contains some zeros then we can divide x by y using the below commands −x[x==0] y yOutput[1] 1 5 3 1 9 1 3 8 9 0 1 7 3 2 3 3 2 9 3 1 9 5 5 2 5 4 4 7 4 5 9 1 9 9 4 2 3 [38] ... Read More