Programming Articles - Page 1606 of 3366

Suppose we have one m x n 2D grid, and that is initialized with these three possible values.-1 for a wall or an obstacle.0 for a gate.INF This is infinity means an empty room.Here 2^31 - 1 = 2147483647 is INF as we may assume that the distance to a gate is less than 2147483647. Fill each empty room with the distance to its nearest gate. If it is impossible to reach a gate, it should be filled with INF.So, if the input is likeINF-10INFINFINFINF-1INF-1INF-10-1INFINFthen the output will be3-101221-11-12-10-134To solve this, we will follow these steps −Define an array dir ... Read More

Suppose we have a binary search tree and a node in it, we have to search the in-order successor of that node in the BST. As we know that the successor of a node p is the node with the smallest key greater than p.val.So, if the input is like root = [2, 1, 3], p = 1, then the output will be 2, To solve this, we will follow these steps −Define recursive method inorderSuccessor(), this will take root and pif root null, then −return nullif val of root val val){          return inorderSuccessor(root->right, p);   ... Read More

Suppose there are two 1D arrays, we have to implement an iterator that will return their elements alternately. There will be two methods −next() − to get next elementhasNext() − to check whether the next element is present or not.So, if the input is like v1 = [1, 2] v2 = [3, 4, 5, 6] , then the output will be [1, 3, 2, 4, 5, 6], To solve this, we will follow these steps −Define one queue q of pairsFrom the initializer ake two arrays v1 and v2, if size of v1, then −insert { 0, 0 } into ... Read More

Suppose we have an unsorted array called nums, we have to reorder it in-place such that nums[0] = nums[2] nums[i+1] is true or i is odd and nums[i] > nums[i+1] is false, thenswap(nums[i], nums[i + 1])Example Let us see the following implementation to get better understanding − Live Demo#include using namespace std; void print_vector(vector

Suppose we have n people (labeled from 0 to n - 1) and among them, there may exist one celebrity. We can say a person x is a celebrity when all the other n - 1 people know x but x does not know any of them. Here we have to find who the celebrity is or verify that there is not one.We are allowed to ask only one question to person ‘A’, that "Hi, A. Do you know B?" to get information of whether A knows B or not. We have to ask minimum number of questions tofind out ... Read More

Suppose we have a list of strings. We have to design an algorithm that can encode the list of strings to a string. We also have to make one decoder that will decode back to the original list of strings. Suppose we have the encoder and decoder installed on these machines, and there are two different functions as follows −Machine 1 (sender) has the functionstring encode(vector

Suppose we have a string s, we have to find all the palindromic permutations of it, there will be no repetition. If no palindromic permutation is there, then simply return empty string.So, if the input is like "aabb", then the output will be ["abba", "baab"]To solve this, we will follow these steps −Define an array retDefine a function solve(), this will take s, sz, one unordered map m, idx initialize it with 0, if sz is same as 0, then −insert s at the end of retreturnevenFound := falseDefine one set visitedfor each key-value pair it of m, do −if ... Read More

Suppose we have n nodes they are labeled from 0 to n-1 and a list of undirected edges [u, v], We have to define a function to check whether these edges make up a valid tree or not.So, if the input is like n = 5, and edges = [[0, 1], [0, 2], [0, 3], [1, 4]], then the output will be trueTo solve this, we will follow these steps −Define a function dfs(), this will take node, par, graph, and another array called visited, if visited[node] is same as 1, then −return trueif visited[node] is same as 2, then ... Read More

The 3Sum Smaller is one of the problem variations in which we need to find the number of triplets in an array such that their sum is less than a given target. We are given an array of n integers called nums and a target value, and we have to find the number of index triplets (i, j, k) where i, j, k are indices of an array all in range 0 to n – 1, such that they satisfy the condition: nums[i] + nums[j] + nums[k]

In this article will explain a popular coding problem that involves verifying whether a given preorder sequence can represent a valid binary search tree (BST). We will discuss the problem statement, provide examples, algorithm to solve, and a C++ implementation of the solution. Problem Statement Algorithm to Solve Problem C++ Program Time and Space Complexity Verify Preorder Sequence in Binary Search Tree Given an array containing the preorder traversal of a binary tree, we need to verify whether it ... Read More