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Programming Articles
Page 1248 of 2547
Count ordered pairs with product less than N in C++
We are given a number N. The goal is to find ordered pairs of positive numbers such that their product is less than N.We will do this by starting from i=1 to i
Read MoreHow to find the mean of row values in an R data frame using dplyr?
The mean of row values can be found by using rowwise function of dplyr package along with the mutate function to add the new column of means in the data frame. The rowwise function actually helps R to read the values in the data frame rowwise and then we can use mean function to find the means as shown in the below examples.Example1Consider the below data frame:> x1 x2 df1 df1Output x1 x2 1 0 8 2 2 3 3 2 5 4 0 5 5 3 2 6 0 10 7 3 5 8 1 7 9 0 4 ...
Read MoreCount pairs (a, b) whose sum of cubes is N (a^3 + b^3 = N) in C++
We are given a number N. The goal is to find ordered pairs of positive numbers such that the sum of their cubes is N.We will do this by finding solutions to the equation a3 + b3 = N. Where a is not more than cube root of N and b can be calculated as cube root of (N-a3).Let’s understand with examples.Input N=35Output Count of pairs of (a, b) where a^3+b^3=N: 2Explanation Pairs will be (2, 3) and (3, 2). 23+33=8+27=35Input N=100Output Count of pairs of (a, b) where a^3+b^3=N: 0Explanation No such pairs possible.Approach used in the below program is as followsWe take integer N.Function ...
Read MoreHow to perform chi square test for goodness of fit in R?
The chi square test for goodness of fit is a nonparametric test to test whether the observed values that falls into two or more categories follows a particular distribution of not. We can say that it compares the observed proportions with the expected chances. In R, we can perform this test by using chisq.test function. Check out the below examples to understand how it is done.Example1> x1 x1Output[1] 9 4 1 9 6 6 1 6 0 0 5 8 8 3 7 8 0 3 3 9 6 0 3 8 2 0 8 5 9 1 3 4 ...
Read MoreCount pairs (a, b) whose sum of squares is N (a^2 + b^2 = N) in C++
We are given a number N. The goal is to find ordered pairs of positive numbers such that the sum of their squares is N.We will do this by finding solutions to the equation a2+ b2 = N. Where a is not more than square root of N and b can be calculated as square root of (N-a2).Let’s understand with examples.Input N=100Output Count of pairs of (a, b) where a^3+b^3=N: 2Explanation Pairs will be (6, 8) and (8, 6). 62+82=36+64=100Input N=11Output Count of pairs of (a, b) where a^3+b^3=N: 0Explanation No such pairs possible.Approach used in the below program is as followsWe take integer N.Function squareSum(int ...
Read MoreCount pairs (i,j) such that (i+j) is divisible by both A and B in C++
We are given variables N, M, A and B. The goal is to find ordered pairs of positive numbers( i, j ) such that their sum is divisible by both A and B. And 1
Read MoreProgram to find Inorder Successor of a binary search tree in C++
Suppose we have a binary search tree BST and another value of a node, we have to find the in-order successor of that node in the BST. As we all know that the successor of a node p is the node with the smallest key greater than the value of p.So, if the input is likeAnd p = 1, then the output will be 2, To solve this, we will follow these steps −Define recursive method inorderSuccessor(), this will take root and pif root null, then:return nullif val of root val val){ return inorderSuccessor(root->right, ...
Read MoreWhat are the different types of point available in geom_point of ggplot2 package in R?
We can create a point chart using ggplot2 package but that point not necessarily to be in circular shape, we have twenty-five shape options for those points in ggplot2. While creating a point chart using ggplot2, we can use shape argument inside geom_point to see the difference among these twenty-five shapes.ExampleConsider the below data frame:> set.seed(1957) > x y df dfOutput x y 1 0.7028704 1.6664500 2 0.9672393 1.0456639 3 1.3102736 0.2495795 4 0.3389941 0.2141513 5 0.5867095 0.4417377 6 0.4257543 0.6533757 7 0.9106756 0.3611954 8 1.0444729 1.3770588 9 ...
Read MoreCount pairs from two arrays having sum equal to K in C++
We are given two arrays Arr1[] and Arr2[] and a number K. The goal is to find unique pairs of elements of both arrays such that their sum is K. Pairs will be of form ( Arr1[i], Arr2[j] ) where Arr1[i]+Arr2[j]==K.We will traverse using two loops for i and j. If sum (Arr1[i]+Arr2[j])==K. And the pair doesn’t exist in unordered_map. Add it to the map and increment count.Let’s understand with examples.Input Arr1[]={ 1, 3, 2, 4, 3, 2 }; Arr2[]={ 0, 2, 1, 2, 3 }; K=4Output Number of pairs with sum K : 4Explanation Pairs will be ( Arr1[0], Arr2[4] ) → ...
Read MoreHow to find the correlation coefficient between two data frames in R?
If two data frames in R have equal number of columns then we can find the correlation coefficient among the columns of these data frames which will be the correlation matrix. For example, if we have a data frame df1 that contains column x and y and another data frame df2 that contains column a and b then the correlation coefficient between df1 and df2 can be found by cor(df1, df2).Example1Consider the below data frame:> x1 x2 df1 df1Output x1 x2 1 39.56630 38.25632 2 39.43689 44.14647 3 40.80479 37.43309 4 ...
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