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C++ Articles
Page 202 of 597
Positive elements at even and negative at odd positions (Relative order not maintained) in C++
In this problem, we are given an array and our task is to convert the array in such a way that all positive numbers are at even index places and all negative numbers are at odd index places.There might be an unequal number of positive and negative values, in this case, we will not move extra values.Let’s take an example to understand the problem, Input − {3, 5, -1, 19, -7, -2}Output − {3, -1, 5, -7, 19, -2}To solve this problem, we will have to find the element which is out of order in the array. There can be ...
Read MorePosition of the K-th set bit in a number in C++
In this problem, we are given two integers N and K. Our task is to find the index of Kth set a bit of the number N, counted from right.Set bits are checked from the binary representation of the number. The indexing in binary representation starts from index 0 from the right direction and propagates towards left.Example − in the binary number ‘011101’, at index 0 from right we have 1, at index 1 from right we have 0, and so on.Now, let’s take an example to understand the problemInput − N = 6, K = 2Output − 2Explanation − ...
Read MorePosition of robot after given movements in C++
In this problem, we are given a robot that moves in all four directions but only one move. The directions are up(‘U’), down(‘D’), left(‘L’), right(‘R’). And we are given a string that contains initials of directions of the number. Our task is to print the final position of the robot, given the initial position of the robot is (0, 0).Let’s take an example to understand the problemInput − input: ‘LDRRUL’Output − (0, 0)Explanation −L (left) : (0, 0) -> (-1, 0) D (down) : (-1, 0) -> (-1, -1) R (right) : (-1, -1) -> (0, -1) R (right) : ...
Read MorePosition of rightmost set bit in C++
In this problem, we are given a number N. Our task is to print the index of the rightmost set bit of the number.Let’s take an example to understand the problem, Input − 4Output − 3Explanation − binary of 4 is 100, the index of the rightmost set bit is 3.To solve this problem, a simple solution would be shifting the number till a set bit is encountered but this could take a lot of computation if the number is large.A more efficient solution will be using boolean algebra. For this we will first calculate 2’s complement of the number, ...
Read MorePosition of rightmost different bit in C++
In this problem, we are given two numbers N and M. Our task is to find the index of the rightmost different bit in the binary representation of the number.Let’s take an example to understand the problem, Input − N = 12 , M = 9Output − 2Explanation − (12)2 = 1100 and (10)2 = 1010.The second bit from right is a different bit.To solve this problem, we will have to find all the different bits of the numbers. To find all different bits we will find xor of M and N. Then we will find the rightmost bit of M^N.This seems ...
Read MorePosition of rightmost common bit in two numbers in C++
In this problem, we are given two numbers M and N. Our task is to print the position (index) of the rightmost common bit of the two numbers.Let’s take an example to understand the problem, Input − N = 4 , M = 7Output − 3Explanation − (4)2 = 100 , (7)2 = 111. The rightmost common bit is at index 3.To solve this problem, we will have to find all the same bits of the numbers. To find all same bits we will find xor of M and N. Then we will find the rightmost bit in the negation ...
Read MorePosition of rightmost bit with first carry in sum of two binary in C++
In this problem, we are given two positive integers N and M. Our task is to print the rightmost bit that generates the first carry bit in the binary addition of the sum of N and M.Let’s take an example to understand the problem, Input − N = 5, M = 14Output − 3Explanation −(5)2 = 0101 , (14)2 = 1110 Sum 0101 + 1110 10011To solve this problem, we will consider some observations from boolean algebra.The sum will generate a carry when both numbers are 1. So, we will find all bits where carry is generated. ...
Read MorePosition of a person diametrically opposite on a circle in C++
In this problem, we are given two integers N and M. there is a circle and N people are standing on it. M denotes the position of a person. Our task is to print the position of the person opposite to M.Let’s take an example to understand the problem, Input − N = 6, M = 3Output − 6Explanation −To solve this problem, there will be two cases, one if the position is greater than half the position (second half), the opposition will be the first half and vise versa.Let’s create a formula for this mathematically, Case 1 − if ...
Read MorePosition after taking N steps to the right and left in an alternate manner in C++
In this problem, we are given three integers N, A and B. there is a person who is standing at coordinate 0 movesA step towards the right and then B step towards left. Then again right. Our task is to print the final position of the element after N moves.Let’s take an example to understand the problem, Input − N = 4, A = 3, B = 1Output −Explanation −1st move -> right 3, +3 2nd move -> left 1, -1 3rd move -> right 3, +3 4th move -> left 1, -1. Position after 4 moves, +3-1+3-1 = 4.To ...
Read MorePopulate Inorder Successor for all nodes in C++
In this problem, we are given a tree. The structure contains a pointer next. Our task is to populate this pointer with the inorder successor of the node.struct node { int value; struct node* left; struct node* right; struct node* next; }All the next pointer are set to NULL and we have to set the pointer to the inorder successor of the node.Inorder traversal − This traverses in the following form, Left node -> root Node -> right node.Inorder successor − the inorder successor is the node that comes after the current node is the inorder ...
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