The bitonicity of an array is defined using the following syntax −To find bitonicity of an array based on its elements is −Bitonicity = 0 , initially arr[0] i from 0 to n Bitonicity = Bitonicity+1 ; if arr[i] > arr[i-1] Bitonicity = Bitonicity-1 ; if arr[i] < arr[i-1] Bitonicity = Bitonicity ; if arr[i] = arr[i-1]ExampleThe code for finding the bitonicity of an array we have used a variable called bitonicity, that changes its based on the comparison of the current and previous elements of the array. The above logic updates the bitonicity of the array and final bitonicity ... Read More

A tetrahedron is a pyramid with triangular base i.e. it has a base that is a triangle and each side has a triangle. All the three triangles converge to a point. As in the figure, Area of Tetrahedron = (√3)a2ExampleThe code to find the area of tetrahedron uses the math library to find the square and square-root of a number using sqrt and pow methods. For calculating the area we take a floating point and the value of the expression "((sqrt(3)*a*a))" is given to it.#include #include int main() {    int a= 5;    float area, volume;   ... Read More

DFA stands for Deterministic Finite Automata. It is a finite state machine that accepts or a string based on its acceptor.Here, we are going to make a DFA that accepts a string that starts and ends with a. The input is from the set (a, b). Based on this we will design a DFA. Now, Let's discuss some valid and invalid cases that are accepted by a DFA.Strings that are accepted by DFA: ababba, aabba, aa, a.Strings that are not accepted by DFA: ab, b, aabab.ExampleThis program check for a string that starts and ends with a. This DFA will ... Read More

Here we will see one problem. We have one binary array. It has n elements. Each element will be either 0 or 1. Initially, all elements are 0. Now we will provide M commands. Each command will contain start and end indices. So command(a, b) is indicating that the command will be applied from element at position a to element at position b. The command will toggle the values. So it will toggle from ath index to bth index. This problem is simple. check the algorithm to get the concept.AlgorithmtoggleCommand(arr, a, b)Begin    for each element e from index a ... Read More

Here we will see the area of the biggest square that can be inscribed in an equilateral triangle. The side of the triangle is ‘a’ and the side of the square is x.The side of the triangle ‘a’ is −So x is −Example#include #include using namespace std; float areaSquare(float a) { //a is side of triangle    if (a < 0 ) //if a is negative, then this is invalid       return -1;    float area = a / (1 + 2/sqrt(3));    return area; } int main() {    float a = 7;    cout

Here we will see the area of biggest Reuleaux triangle inscribed within a square. The side of the square is ‘a’. And the height of the Reuleaux triangle is h.The height of the Reuleaux triangle is same as a. So a = h. So the area of Reuleaux triangle is −Example#include #include using namespace std; float areaReuleaux(float a) { //side of square is a    if (a < 0) //if a is negative it is invalid       return -1;    float area = ((3.1415 - sqrt(3)) * (a) * (a))/2;    return area; } int main() {    float side = 8;    cout

Here we will see the area of biggest Reuleaux triangle inscribed within a square, That square is inscribed inside one circle. The side of the square is ‘a’. The radius of the circle is ‘r’. As we know that the diagonal of the square is the diameter of the circle. So −2𝑟 = 𝑎√2 𝑎 = 𝑟√2And the height of the Reuleaux triangle is h.The height of the Reuleaux triangle is same as a. So a = h. So the area of Reuleaux triangle is −Example#include #include using namespace std; float areaReuleaux(float r) { //radius of ciecle is ... Read More

Here we will see the area of biggest Reuleaux triangle inscribed within a square, that square is inscribed inside one right angled triangle. The side of the square is ‘a’. The height of the Reuleaux triangle is x. The base of the triangle is b, height of the triangle is l, and the hypotenuse is h.We know that the side of square inscribed in a Right angled triangle with height l and base b is −The height of the Reuleaux triangle is same as a. So a = x. So the area of Reuleaux triangle is −Example#include #include ... Read More

Here we will see the area of biggest Reuleaux triangle inscribed within a square, that square is inscribed inside one ellipse. We know that the major axis length is 2a, and the minor axis length is 2b. The side of the square is ‘x’, and the height of the Reuleaux triangle is h.We know that the side of a square inscribed in an ellipse with major axis 2a and minor axis 2b is −The height of the Reuleaux triangle is same as a. So h = x. So the area of Reuleaux triangle is −.Example#include #include using namespace ... Read More

Here we will see the area of biggest Reuleax triangle inscribed within a square which is inscribed in a regular hexagon. Suppose ‘a’ is the side of the hexagon. The side of the square is x and the height of the Reuleaux triangle is h.From the formula of each side of inscribed square inside one hexagon is −𝑥 = 1.268𝑎The height of the Reuleaux triangle is the same as x. So x = h. So the area of the Reuleaux triangle is −Example#include #include using namespace std; float areaReuleaux(float a) { //side of hexagon is a    if ... Read More