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Server Side Programming Articles
Page 1665 of 2107
Finding relative order of elements in list in Python
We are given a list whose elements are integers. We are required to find the relative order which means if they are sorted in ascending order then we need to find index of their positions.With sorted and indexWe first sort the entire list and then find out the index of each of them after the sorting.Example Live DemolistA = [78, 14, 0, 11] # printing original list print("Given list is : ", listA) # using sorted() and index() res = [sorted(listA).index(i) for i in listA] # printing result print("list with relative ordering of elements : ", res)OutputRunning the above code gives ...
Read MoreFind whether all tuple have same length in Python
In this article we will find out if all the tuples in a given list are of same length.With lenWe will use len function and compare its result to a given value which we are validating. If the values are equal then we consider them as same length else not.Example Live DemolistA = [('Mon', '2 pm', 'Physics'), ('Tue', '11 am', 'Maths')] # printing print("Given list of tuples:", listA) # check length k = 3 res = 1 # Iteration for tuple in listA: if len(tuple) != k: res = 0 break # Checking if ...
Read MoreFind top K frequent elements from a list of tuples in Python
We have a list of tuples. In it we are required to find the top k frequent element. If k is 3 we are required to find the top three elements from the tuples inside the list.With defaultdictWe put the the elements into a dictionary container using defaultdict. Then find out only the elements which satisfy that top k conditions.Example Live Demoimport collections from operator import itemgetter from itertools import chain # Input list initialization listA = [[('Mon', 126)], [('Tue', 768)], [('Wed', 512)], [('Thu', 13)], [('Fri', 341)]] # set K K = 3 #Given list print("Given list:", listA) print("Check value:", K) ...
Read MoreFind the tuples containing the given element from a list of tuples in Python
A list can have tuples as its elements. In this article we will learn how to identify those tuples which contain a specific search element which is a string.With in and conditionWe can design a follow with in condition. After in we can mention the condition or a combination of conditions.Example Live DemolistA = [('Mon', 3), ('Tue', 1), ('Mon', 2), ('Wed', 3)] test_elem = 'Mon' #Given list print("Given list:", listA) print("Check value:", test_elem) # Uisng for and if res = [item for item in listA if item[0] == test_elem and item[1] >= 2] # printing res print("The tuples satisfying the ...
Read MoreMaximum Score Words Formed by Letters in C++
Suppose we have a list of words, a list of single letters and score for every character. We have to find the maximum score of any valid set of words formed by using the given letters.We may not use all characters in letters and each letter can only be used once. Score of letters 'a', 'b', 'c', ... ,'z' is given by score[0], score[1], ... , score[25] respectively.So, if the input is like words = ["god", "good", "toc", "cat"], letters = [a, g, o, o, d, d, d, c, t, t] and score = [5, 0, 8, 3, 0, 0, ...
Read MoreFind the Number Occurring Odd Number of Times using Lambda expression and reduce function in Python
In this article we are required to find that number from the list which occurs odd number of times in the given list. We are also required to use the Lambda function and the reduce function.We design a function where the reduce function is used by applying the Lambda function to check if the element is present odd number of times.Example Live Demofrom functools import reduce def oddcount(i): print(reduce(lambda x, y: x ^ y, i)) listA = [12, 34, 12, 12, 34] print("Given list:", listA) print("The element present odd number of times:") oddcount(listA)OutputRunning the above code gives us the following ...
Read MoreCheck If It Is a Good Array in C++
Suppose we have an array called nums of positive integers. We have to select some subset of nums, then multiply each element by an integer and add all these numbers. The array will be a good array if we can get a sum of 1 from the array by any possible subset and multiplicand.We have to check whether the array is good or not.So, if the input is like [12, 23, 7, 5], then the output will be True, this is because If we take numbers 5, 7, then 5*3 + 7*(-2) = 1To solve this, we will follow these ...
Read MoreFind the list elements starting with specific letter in Python
In this article we will find all those elements from a list which start with specific letter.With index and lowerWe use the lower function so that the test later can match with the first letter of the the elements in the list irrespective of the case. Then we use the index at 0 so that the first letter of the elements in a list are compared with the test letter.Example Live DemolistA = ['Mon', 'Tue', 'Wed', 'Thu'] # Test with letter test = 'T' # printing original list print("Given list " ,listA) # using lower and idx res = [idx for ...
Read MoreTiling a Rectangle with the Fewest Squares in C++
Suppose we have a rectangle of size n x m. We have to find the minimum number of integers sided square objects that can tile the rectangles.So, if the input is like n = 2 and m = 3,then the output will be 3, as we need three blocks.To solve this, we will follow these steps −Define one map mres := infDefine a function dfs(), this will take n, m, an array h, cnt,if cnt >= res, then −returnisFull := truepos := -1, minH := inffor initialize i := 1, when i
Read MoreFind most frequent element in a list in Python
In this article we will see how to find the element which is most common in a given list. In other words, the element with highest frequency.With max and countWe apply why the set function to get the unique elements of the list and then keep account of each of those elements in the list. Finally apply a max function to get the element with highest frequency.Example Live Demo# Given list listA = [45, 20, 11, 50, 17, 45, 50, 13, 45] print("Given List:", listA) res = max(set(listA), key = listA.count) print("Element with highest frequency:", res)OutputRunning the above code gives us ...
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