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Python Articles
Page 850 of 855
What does 'is not' operator do in Python?
In Python, is and is not operators are called identity operators. Each object in computer's memory is assigned a unique identification number (id) by Python interpreter. Identity operators check if id() of two objects is same. 'is not' operator returns true of id() values are different and false if they are same.>>> a=10 >>> b=a >>> id(a), id(b) (490067904, 490067904) >>> a is not b False >>> a=10 >>> b=20 >>> id(a), id(b) (490067904, 490068064) >>> a is not b True
Read MoreWhat does 'in' operator do in Python?
In Python, in and not in operators are called membership operators. Their purpose is to check if an object is a member of a certain sequence object like string, list, or tuple. The in operator returns true if object is present in sequence, false if not found>>> 'p' in 'Tutorialspoint' True >>> 'c' in 'Tutorialspoint' False >>> 10 in range(0,5) False
Read MoreHow do we convert a string to a set in Python?
Python’s standard library contains built-in function set() which converts an iterable to set. A set object doesn’t contain repeated items. So, if a string contains any character more than once, that character appears only once in the set object. Again, the characters may not appear in the same sequence as in the string as set() function has its own hashing mechanism>>> set("hello") {'l', 'h', 'o', 'e'}
Read MoreHow to convert an object x to a string representation in Python?
Most commonly used str() function from Python library returns a string representation of object.>>> no=100 >>> str(no) '100' >>> L1=[1,2,3,4] >>> str(L1) '[1, 2, 3, 4]' >>> d={'a': 1, 'b': 2, 'c': 3, 'd': 4} >>> str(d) "{'a': 1, 'b': 2, 'c': 3, 'd': 4}"However, repr() returns a default and unambiguous representation of the object, where as str() gives an informal representation that may be readable but may not be always unambiguous.>>> str(d) "{'a': 1, 'b': 2, 'c': 3, 'd': 4}" >>> repr(d) "{'a': 1, 'b': 2, 'c': 3, 'd': 4}" >>> repr(L1) '[1, 2, 3, 4]' >>> repr(no) '100'
Read MoreHow to Find the Sum of Natural Numbers using Python?
You can use while loop to successively increment value of a variable i by one and adding it cumulatively.s,i=0,0 n=10 while i
Read MoreHow to generate armstrong numbers in Python?
Any three digit number is called an Armstrong number of sum of cube of its digits equals the number itself. In order to check if a number satisfies this condition, each digit from it is successively separated from right and its cube is cumulatively added. In the end if the sum is found to be equal to original number, it is called Armstrong number.ExampleFollowing Python code prints all armstrong numbers between 100 to 999for num in range(100, 1000): temp=num sum=0 while temp>0: digit=temp%10 sum=sum+digit**3 temp=temp//10 if sum==num: ...
Read MoreHow to get the number of capture groups in Python regular expression?
The following code gets the number of captured groups using Python regex in given stringExampleimport re m = re.match(r"(\d)(\d)(\d)", "632") print len(m.groups())OutputThis gives the output3
Read MoreHow to write Python regular expression to get all the anchor tags in a webpage?
The following code extracts all tags in the given stringExampleimport re rex = re.compile(r'[\]') l = "this is text1 hi this is text2" print rex.findall(l)Output['', '']
Read MoreHow to use wildcard in Python regular expression?
The following code uses the Python regex .()dot character for wildcard which stands for any character other than newline.Exampleimport re rex = re.compile('th.s') l = "this, thus, just, then" print rex.findall(l)OutputThis gives the output['this', 'thus']
Read MoreHow to find all adverbs and their positions in a text using python regular expression?
As per Python documentationIf one wants more information about all matches of a pattern than the matched text, finditer() is useful as it provides match objects instead of strings. If one was a writer who wanted to find all of the adverbs and their positions in some text, he or she would use finditer() in the following manner −>>> text = "He was carefully disguised but captured quickly by police." >>> for m in re.finditer(r"\w+ly", text): ... print('%02d-%02d: %s' % (m.start(), m.end(), m.group(0))) 07-16: carefully 40-47: quickly
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