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Programming Articles - Page 2475 of 3363
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In this section we will see some examples of code shortening strategy for competitive programming. Suppose we have to write some large amount of codes. In that code, we can follow some strategy to make them more short.We can change the type-name to make it short. Please check the code to get the ideaExample Code#include using namespace std; int main() { long long x = 10; long long y = 50; cout
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Here we will see one space optimized approach for LCS problem. The LCS is the longest common subsequence. If two strings are “BHHUBC” and “HYUYBZC”, then the length of the subsequence is 4. One dynamic programming approach is already their, but using the dynamic programming approach, it will take more space. We need table of order m x n, where m is the number of characters in first string, and n is the number of characters in the second string.Here we will see how to implement this algorithm using O(n) amount of auxiliary space. If we observe the old approach ... Read More
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Suppose we have one graph like below. That graph is Peterson graph. The vertices are numbered from 0 through 9. Each vertex has some letters. Let consider one walk W, in that graph, where L vertices are used. A string S with L letters is realized by the walk W when the letter sequence in W and S are same. We can visit the vertices multiple times.For example, one string S is like “ABBECCD”, this is realized by the walk (0, 1, 6, 9, 7, 2, 3). Our task is to find such walk, and if that walk is present, ... Read More
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Suppose we have one integer variable whose size is 4 byte, another pointer variable is there, whose size is 8 bytes. So what will be the output of the following?Example#include using namespace std; main() { int a[4][5][6]; int x = 0; int* a1 = &x; int** a2 = &a1; int*** a3 = &a2; cout
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Here we will see the Osiris number. An Osiris number is such kind of number that are equal to the sum of permutations of sub-samples of their own digits. Suppose the number is 132. Then if we calculate {12 + 21 + 13 + 31 + 23 + 32} this is also 132. So the number is Osiris number. We have to check whether the given number is Osiris number or not.Approach is simple. If we analyze the numbers, each digit is occurring twice so they are in ones position and tens position. So we can check by multiplying 11 ... Read More
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The java.lang.String class represents an immutable sequence of characters and cannot be changed once created. We need to instantiate this class or assign values directly to its literal to create a string in Java. The String class does not provide any built-in method to sort the contents of a string. To sort a String, we need to convert it into a character array using the toCharArray() method and sort the array. To sort a character array, we can either use the Arrays.sort() method or use sorting algorithms. Since the given task is to sort a string without using any predefined methods, we ... Read More
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For this problem, to add elements of two given arrays we have some constraints based on which the added value will get changed. the sum of two given arrays a[] & b[] is stored into to third array c[]in such a way that they gave the some of the elements in single digit. and if the number of digits of the sum is greater than 1, then the element of the third array will split into two single-digit elements. For example, if the sum occurs to be 27, the third array with store it as 2, 7.Input: a[] = {1, ... Read More
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The article will explain the use of object cloning in Java and provide an appropriate example to clarify the problem. What is the Object Cloning in Java? In Java, object cloning is a way to create an exact copy of an object. We can use the clone() method provided by the Object class to create a clone of an object. When an object is cloned, a new instance of the same class is created, and the fields of the original object are copied to the new object. The Cloneable interface must be implemented by a class whose object is ... Read More
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A BST or binary search tree is a form of binary tree that has all left nodes smaller and all right nodes greater than the root value. For this problem, we will take a binary tree and add all the values greater than the current node to it. the problem “ add all greater values to every node in BST” is simplified as for a BST add all the node values that are greater than the current node value to that node value.Add all greater values to each node in the BST Problem Statement:Given a Binary Search Tree (BST), we ... Read More
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The linked list representation of a number is provided in such a way that the all nodes of the linked list are treated as one digit of the number. The node stores the number such that the first element of the linked list holds the most significant digit of the number, and the last element of the linked list holds the least significant bit of the number. For example, the number 202345 is represented in the linked list as (2->0->2->3->4->5).And to add one to this linked list represented number we have to check the value of the least significant bit ... Read More