Maximum Profit by Buying and Selling a Share at Most Twice

Chandu yadav
Updated on 17-Jun-2020 07:07:12

572 Views

In a trading, one buyer buys and sells the shares, at morning and the evening respectively. If at most two transactions are allowed in a day. The second transaction can only start after the first one is completed. If stock prices are given, then find the maximum profit that the buyer can make.Input and OutputInput: A list of stock prices. {2, 30, 15, 10, 8, 25, 80} Output: Here the total profit is 100. As buying at price 2 and selling at price 30. so profit 28. Then buy at price 8 and sell it again at price 80. So ... Read More

Maximum Sum Increasing Subsequence

George John
Updated on 17-Jun-2020 07:03:35

621 Views

Maximum Sum Increasing subsequence is a subsequence of a given list of integers, whose sum is maximum and in the subsequence, all elements are sorted in increasing order.Let there is an array to store max sum increasing subsequence, such that L[i] is the max sum increasing subsequence, which is ending with array[i].Input and OutputInput: Sequence of integers. {3, 2, 6, 4, 5, 1} Output: Increasing subsequence whose sum is maximum. {3, 4, 5}.AlgorithmmaxSumSubSeq(array, n)Input: The sequence of numbers, number of elements.Output: Maximum sum of the increasing sub sequence.Begin    define array of arrays named subSeqLen of size n.    add ... Read More

Maximum Sum Rectangle in a 2D Matrix

karthikeya Boyini
Updated on 17-Jun-2020 07:02:10

2K+ Views

A matrix is given. We need to find a rectangle (sometimes square) matrix, whose sum is maximum.The idea behind this algorithm is to fix the left and right columns and try to find the sum of the element from the left column to right column for each row, and store it temporarily. We will try to find top and bottom row numbers. After getting the temporary array, we can apply the Kadane’s Algorithm to get maximum sum sub-array. With it, the total rectangle will be formed.Input and OutputInput: The matrix of integers.  1  2 -1 -4 -20 -8 -3  4 ... Read More

Min Cost Path

Chandu yadav
Updated on 17-Jun-2020 06:57:58

770 Views

A matrix of the different cost is given. Also, the destination cell is provided. We have to find minimum cost path to reach the destination cell from the starting cell (0, 0).Each cell of the matrix represents the cost to traverse through that cell. From a cell, we cannot move anywhere, we can move either to the right or to the bottom or to the lower right diagonal cell, to reach the destination.Input and OutputInput: The cost matrix. And the destination point. In this case the destination point is (2, 2). 1 2 3 4 8 2 1 5 3 ... Read More

Minimum Cost Polygon Triangulation

Samual Sam
Updated on 17-Jun-2020 06:56:14

956 Views

When nonintersecting diagonals are forming a triangle in a polygon, it is called the triangulation. Our task is to find a minimum cost of triangulation.The cost of triangulation is the sum of the weights of its component triangles. We can find the weight of each triangle by adding their sides, in other words, the weight is the perimeter of the triangle.Input and OutputInput: The points of a polygon. {(0, 0), (1, 0), (2, 1), (1, 2), (0, 2)} Output: The total cost of the triangulation. Here the cost of the triangulation is 15.3006.AlgorithmminCost(polygon, n)Here cost() will be used to calculate ... Read More

Minimum Initial Points to Reach Destination

Samual Sam
Updated on 17-Jun-2020 06:54:13

1K+ Views

To start from the top-left corner of a given grid, one has to reach the bottom-right corner. Each cell in the grid contains a number, the number may positive or negative. When the person reaches a cell (i, j) the number of tokens he has, may be increased or decreased along with the values of that cell. We have to find the minimum number of initial tokens are required to complete the journey.There are some rules −We can either move to the right or to the bottom.We cannot move to a cell (i, j) if our total token is less ... Read More

Get Number of Days in a Specified Month using JavaScript

Nishtha Thakur
Updated on 17-Jun-2020 06:47:45

1K+ Views

To get numbers of days in a month, use the getDate() method and get the days.ExampleYou can try to run the following code to get a number of days in a month −Live Demo                 var days = function(month,year) {          return new Date(year, month, 0).getDate();       };       document.write("Days in July: "+days(7, 2012)); // July month       document.write("Days in September: "+days(9, 2012)); // September Month           OutputDays in July: 31 Days in September: 30

Format a Rounded Number to N Decimals Using JavaScript

Anvi Jain
Updated on 17-Jun-2020 06:45:36

493 Views

Use the toFixed() method to format a rounded number to N decimals. The toFixed() method formats a number with a specific number of digits to the right of the decimal.ExampleYou can try to run the following code to form a rounded number to N decimals −Live Demo           JavaScript toFixed() Method                        var num = 15;          document.write("num.toFixed() is : " + num.toFixed());          document.write("");          document.write("num.toFixed() is : " + num.toFixed(2));          document.write("");          document.write("num.toFixed() is : " + num.toFixed(1));          document.write("");           Outputnum.toFixed() is : 15 num.toFixed() is : 15.00 num.toFixed() is : 15.0

Convert String with Scientific Notation to JavaScript Number Format

Jennifer Nicholas
Updated on 17-Jun-2020 06:44:36

1K+ Views

To convert a string with Scientific Notation, use the Number function. Pass the value to this function.ExampleYou can try to run the following code to convert a string to correct number format −Live Demo                    document.write("String with Scientific Notation converted below:");          document.write(Number("7.53245683E7"));           OutputString with Scientific Notation converted below: 75324568.3

Test if a JavaScript Cookie has Expired

mkotla
Updated on 17-Jun-2020 06:43:19

3K+ Views

To test if a cookie has expired in JavaScript, add the following condition and check −if( !($.cookie('myCookie') === null) ) {    // Do something (cookie exists) } else {    // Do something (cookie expired) }You can also check it using a single line code −checkCookie = $.cookie('myCookie') === null ? ( /*Condition TRUE...*/ ) : ( /*Condition FALSE...*/ );

Advertisements