Python program to print the elements of an array present on odd position

When we need to print elements at odd positions in a Python list, we can use a for loop with the range() function. By starting from index 1 and using a step size of 2, we can access only the odd-positioned elements.

Using range() with Step Size

The most common approach is to iterate through odd indices using range(1, len(list), 2) ?

my_list = [31, 42, 13, 34, 85, 0, 99, 1, 3]
print("The list is:")
print(my_list)
print("The elements in odd positions are:")
for i in range(1, len(my_list), 2):
    print(my_list[i])

The output of the above code is ?

The list is:
[31, 42, 13, 34, 85, 0, 99, 1, 3]
The elements in odd positions are:
42
34
0
1

Using List Slicing

Another approach is to use list slicing with [1::2] to get all odd-positioned elements ?

my_list = [31, 42, 13, 34, 85, 0, 99, 1, 3]
print("The list is:")
print(my_list)
print("The elements in odd positions are:")
odd_elements = my_list[1::2]
for element in odd_elements:
    print(element)

The list is:
[31, 42, 13, 34, 85, 0, 99, 1, 3]
The elements in odd positions are:
42
34
0
1

Using enumerate()

We can also use enumerate() to get both index and value, then check if the index is odd ?

my_list = [31, 42, 13, 34, 85, 0, 99, 1, 3]
print("The list is:")
print(my_list)
print("The elements in odd positions are:")
for index, element in enumerate(my_list):
    if index % 2 == 1:
        print(element)

The list is:
[31, 42, 13, 34, 85, 0, 99, 1, 3]
The elements in odd positions are:
42
34
0
1

Comparison

Conclusion

Use range(1, len(list), 2) for simple iteration or list slicing [1::2] for concise code. Both methods efficiently access elements at odd positions (indices 1, 3, 5, etc.).