Python Program to Get K initial powers of N

When it is required to get the specific number of powers of a number, the ** operator is used along with list comprehension to generate the first K powers of N.

Syntax

The basic syntax for calculating powers in Python ?

# Using ** operator
result = base ** exponent

# Using list comprehension for multiple powers
powers = [base ** i for i in range(k)]

Example

Below is a demonstration of getting K initial powers of N ?

n = 4
k = 5

print("The value n is:", n)
print("The value of k is:", k)

result = [n ** index for index in range(0, k)]

print("The first", k, "powers of", n, ":")
print(result)

The value n is: 4
The value of k is: 5
The first 5 powers of 4 :
[1, 4, 16, 64, 256]

How It Works

The list comprehension iterates through numbers from 0 to k-1:

• 4⁰ = 1

• 4¹ = 4

• 4² = 16

• 4³ = 64

• 4⁴ = 256

Using a Function

You can create a reusable function for this operation ?

def get_k_powers(n, k):
    """Return first k powers of n"""
    return [n ** i for i in range(k)]

# Example usage
base = 3
count = 6
powers = get_k_powers(base, count)

print(f"First {count} powers of {base}:")
for i, power in enumerate(powers):
    print(f"{base}^{i} = {power}")

First 6 powers of 3:
3^0 = 1
3^1 = 3
3^2 = 9
3^3 = 27
3^4 = 81
3^5 = 243

Conclusion

Use list comprehension with the ** operator to efficiently generate the first K powers of any number N. The pattern [n ** i for i in range(k)] creates powers from n⁰ to n^k-1.