Python program to find word score from list of words

Suppose we have a list of words in lowercase letters. We need to find the total score of these words based on specific vowel counting rules.

Scoring Rules

• Consider vowels as [a, e, i, o, u, y]

• If a word contains an even number of vowels, its score is 2

• If a word contains an odd number of vowels, its score is 1

• The total score is the sum of all individual word scores

Example Analysis

For words = ["programming", "science", "python", "website", "sky"]:

• "programming" has 3 vowels (o, a, i) ? odd ? score = 1
• "science" has 3 vowels (i, e, e) ? odd ? score = 1
• "python" has 2 vowels (y, o) ? even ? score = 2
• "website" has 3 vowels (e, i, e) ? odd ? score = 1
• "sky" has 1 vowel (y) ? odd ? score = 1

Total score: 1 + 1 + 2 + 1 + 1 = 6

Solution Algorithm

Here's the step-by-step approach ?

def solve(words):
    score = 0
    vowels = ['a', 'e', 'i', 'o', 'u', 'y']
    
    for word in words:
        num_vowels = 0
        for letter in word:
            if letter in vowels:
                num_vowels += 1
        
        if num_vowels % 2 == 0:
            score += 2
        else:
            score += 1
    
    return score

words = ["programming", "science", "python", "website", "sky"]
print(solve(words))

6

Optimized Solution Using List Comprehension

We can make the code more concise using Python's built-in functions ?

def solve_optimized(words):
    vowels = set('aeiouy')
    
    total_score = 0
    for word in words:
        vowel_count = sum(1 for letter in word if letter in vowels)
        total_score += 2 if vowel_count % 2 == 0 else 1
    
    return total_score

words = ["programming", "science", "python", "website", "sky"]
print(solve_optimized(words))

6

Step-by-Step Breakdown

Let's trace through the algorithm with detailed output ?

def solve_with_details(words):
    vowels = set('aeiouy')
    total_score = 0
    
    for word in words:
        vowel_count = sum(1 for letter in word if letter in vowels)
        word_score = 2 if vowel_count % 2 == 0 else 1
        total_score += word_score
        
        print(f"'{word}': {vowel_count} vowels ? score = {word_score}")
    
    return total_score

words = ["programming", "science", "python", "website", "sky"]
result = solve_with_details(words)
print(f"\nTotal score: {result}")

'programming': 3 vowels ? score = 1
'science': 3 vowels ? score = 1
'python': 2 vowels ? score = 2
'website': 3 vowels ? score = 1
'sky': 1 vowels ? score = 1

Total score: 6

Conclusion

The word scoring algorithm counts vowels in each word and assigns scores based on even/odd vowel counts. Use a set for vowels to improve lookup efficiency, and consider list comprehensions for more concise code.