Python program to find average score of each students from dictionary of scores

When working with student scores stored in a dictionary, calculating the average score for each student is a common task. In Python, we can achieve this by iterating through the dictionary and computing the mean of each student's scores.

So, if the input is like scores = {'Amal' : [25,36,47,45],'Bimal' : [85,74,69,47],'Tarun' : [65,35,87,14],'Akash' : [74,12,36,75]}, then the output will be [38.25, 68.75, 50.25, 49.25] where 38.25 is average score for Amal, 68.75 is average score for Bimal and so on.

Algorithm

To solve this, we will follow these steps ?

• Create an empty dictionary avg_scores to store results
• For each student name in the scores dictionary, do
  • Calculate average by dividing sum of scores by count of scores
  • Store the result in avg_scores[name]
• Return list of all average values

Example

Let us see the following implementation to get better understanding ?

def solve(scores):
    avg_scores = dict()
    for name in scores:
        avg_scores[name] = sum(scores[name]) / len(scores[name])
    
    return list(avg_scores.values())

scores = {'Amal': [25,36,47,45], 'Bimal': [85,74,69,47], 'Tarun': [65,35,87,14], 'Akash': [74,12,36,75]}
print(solve(scores))

[38.25, 68.75, 50.25, 49.25]

Using Dictionary Comprehension

We can also solve this more concisely using dictionary comprehension ?

def solve_compact(scores):
    avg_scores = {name: sum(score_list) / len(score_list) for name, score_list in scores.items()}
    return list(avg_scores.values())

scores = {'Amal': [25,36,47,45], 'Bimal': [85,74,69,47], 'Tarun': [65,35,87,14], 'Akash': [74,12,36,75]}
print(solve_compact(scores))

[38.25, 68.75, 50.25, 49.25]

Conclusion

Both approaches effectively calculate student averages from a dictionary of scores. The dictionary comprehension method provides a more concise solution, while the traditional loop offers better readability for beginners.