Python program to convert tuple into list by adding the given string after every element

When it is required to convert a tuple into a list by adding a given string after every element, list comprehension provides an elegant solution. This technique creates a new list where each original element is followed by the specified string.

Example

Below is a demonstration of the same −

my_tuple = ((15, 16), 71, 42, 99)

print("The tuple is :")
print(my_tuple)

K = "Pyt"
print("The value of K is :")
print(K)

my_result = [element for sub in my_tuple for element in (sub, K)]

print("The result is :")
print(my_result)

Output

The tuple is :
((15, 16), 71, 42, 99)
The value of K is :
Pyt
The result is :
[(15, 16), 'Pyt', 71, 'Pyt', 42, 'Pyt', 99, 'Pyt']

How It Works

The list comprehension [element for sub in my_tuple for element in (sub, K)] works as follows:

• It iterates through each element sub in the original tuple

• For each element, it creates a temporary tuple (sub, K) containing the original element and the string K

• It then iterates through this temporary tuple, adding both the original element and the string to the result list

• This effectively places the string K after every original element

Alternative Method Using Loop

You can achieve the same result using a traditional for loop ?

my_tuple = ((15, 16), 71, 42, 99)
K = "Pyt"

my_result = []
for element in my_tuple:
    my_result.append(element)
    my_result.append(K)

print("The result is :")
print(my_result)

The result is :
[(15, 16), 'Pyt', 71, 'Pyt', 42, 'Pyt', 99, 'Pyt']

Conclusion

List comprehension provides a concise way to convert a tuple into a list while inserting a string after each element. The nested comprehension iterates through elements and creates pairs, effectively doubling the list size with alternating original elements and the specified string.