Python Program – Convert String to matrix having K characters per row

When it is required to convert a string into a matrix that has K characters per row, we can use string slicing and list comprehension. This technique is useful for formatting text data into fixed-width rows for display or processing.

Method 1: Using String Slicing and List Comprehension

This approach creates a matrix by slicing the string into chunks of K characters ?

def convert_string_to_matrix(text, k):
    matrix = []
    for i in range(0, len(text), k):
        row = list(text[i:i+k])
        matrix.append(row)
    return matrix

# Example usage
my_string = "PythonCode&Learn&ObjectOriented"
print("The string is:")
print(my_string)

K = 3
print(f"\nThe value of K is: {K}")

result = convert_string_to_matrix(my_string, K)
print("\nThe matrix is:")
for row in result:
    print(row)

The string is:
PythonCode&Learn&ObjectOriented

The value of K is: 3

The matrix is:
['P', 'y', 't']
['h', 'o', 'n']
['C', 'o', 'd']
['e', '&', 'L']
['e', 'a', 'r']
['n', '&', 'O']
['b', 'j', 'e']
['c', 't', 'O']
['r', 'i', 'e']
['n', 't', 'e']
['d']

Method 2: Using List Comprehension

A more concise approach using list comprehension for the same result ?

def convert_string_compact(text, k):
    return [list(text[i:i+k]) for i in range(0, len(text), k)]

# Example usage
my_string = "HelloWorld"
K = 4

print("Original string:", my_string)
print(f"K value: {K}")

matrix = convert_string_compact(my_string, K)
print("\nResulting matrix:")
for i, row in enumerate(matrix):
    print(f"Row {i}: {row}")

Original string: HelloWorld
K value: 4

Resulting matrix:
Row 0: ['H', 'e', 'l', 'l']
Row 1: ['o', 'W', 'o', 'r']
Row 2: ['l', 'd']

Method 3: Displaying as Formatted Output

To display the matrix in a more readable format with spaces between characters ?

def display_formatted_matrix(text, k):
    print("Formatted matrix:")
    for i in range(0, len(text), k):
        row_chars = text[i:i+k]
        formatted_row = ' '.join(row_chars)
        print(formatted_row)

# Example usage
my_string = "DataScience"
K = 3

print("Original string:", my_string)
print(f"Characters per row: {K}")
print()

display_formatted_matrix(my_string, K)

Original string: DataScience
Characters per row: 3

Formatted matrix:
D a t
a S c
i e n
c e

Comparison

Conclusion

Converting a string to a matrix with K characters per row can be efficiently accomplished using string slicing. Use list comprehension for concise code or formatted display for visual output.