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Python - Group Concatenate Till K
Group concatenate till K means joining elements within a sequence until encountering a specific delimiter value K. Python provides several approaches including loops, itertools.groupby(), and regular expressions. This technique is useful for splitting data into meaningful chunks based on separator values.
Method 1: Using a Loop and Accumulator
This approach iterates through the list, accumulating elements until the delimiter K is found. When K is encountered, accumulated elements are joined and added to results.
Syntax
''.join(sequence) list_name.append(element)
The join() method concatenates sequence elements into a string, while append() adds elements to a list.
Example
def group_concatenate_till_k(lst, K):
result = []
group = []
for item in lst:
if item == K:
if group: # Only add non-empty groups
result.append(''.join(group))
group = []
else:
group.append(item)
# Add remaining group if not empty
if group:
result.append(''.join(group))
return result
# Example usage
data = ['a', 'b', 'c', '|', 'd', 'e', '|', 'f', 'g']
delimiter = '|'
output = group_concatenate_till_k(data, delimiter)
print("Groups:", output)
Groups: ['abc', 'de', 'fg']
Method 2: Using itertools.groupby()
The groupby() function groups consecutive elements based on a condition, providing a more elegant solution for this problem.
Syntax
itertools.groupby(iterable, key=None)
Returns an iterator of consecutive keys and groups from the iterable, where grouping is determined by the key function.
Example
from itertools import groupby
def group_concatenate_till_k(lst, K):
result = []
for is_not_delimiter, group in groupby(lst, lambda x: x != K):
if is_not_delimiter:
joined_group = ''.join(group)
if joined_group: # Only add non-empty groups
result.append(joined_group)
return result
# Example usage
data = ['a', 'b', 'c', '|', 'd', 'e', '|', 'f', 'g']
delimiter = '|'
output = group_concatenate_till_k(data, delimiter)
print("Groups:", output)
Groups: ['abc', 'de', 'fg']
Method 3: Using String Operations
This method first joins all elements, then splits on the delimiter to create groups efficiently.
Example
def group_concatenate_till_k(lst, K):
# Join all elements and split by delimiter
joined = ''.join(lst)
groups = joined.split(K)
# Filter out empty groups
result = [group for group in groups if group]
return result
# Example usage
data = ['a', 'b', 'c', '|', 'd', 'e', '|', 'f', 'g']
delimiter = '|'
output = group_concatenate_till_k(data, delimiter)
print("Groups:", output)
Groups: ['abc', 'de', 'fg']
Comparison
| Method | Readability | Performance | Best For |
|---|---|---|---|
| Loop & Accumulator | Good | Moderate | Complex conditions |
| itertools.groupby() | Excellent | Good | Clean, functional approach |
| String Operations | Good | Fast | Simple string delimiters |
Conclusion
Group concatenation till K is useful for parsing structured data with delimiters. Use itertools.groupby() for clean, readable code, or string operations for simple cases requiring maximum performance.
