Get first index values in tuple of strings in Python

We have a tuple of strings. We are required to create a list of elements which are the first character of these strings in the tuple.

With index

We design a for loop to take each element and extract the first character by applying the index condition as 0. Then the list function converts it to a list.

Example

 Live Demo

tupA = ('Mon', 'Tue', 'Wed', 'Fri')
# Given tuple
print("Given list : \n" ,tupA)
# using index with for loop
res = list(sub[0] for sub in tupA)
# printing result
print("First index charaters:\n",res)

Output

Running the above code gives us the following result −

Given list :
('Mon', 'Tue', 'Wed', 'Fri')
First index charaters:
['M', 'T', 'W', 'F']

With next and zip

We apply zip to the tuple and then apply next to get the first character of each element.

Example

tupA = ('Mon', 'Tue', 'Wed', 'Fri')
# Given tuple
print("Given list : \n" ,tupA)
# using next and zip
res = list(next(zip(*tupA)))
# printing result
print("First index charaters:\n",res)

Output

Running the above code gives us the following result −

Given list :
('Mon', 'Tue', 'Wed', 'Fri')
First index charaters:
['M', 'T', 'W', 'F']