Buying Cars in Python

Suppose we have a list of prices of cars for sale, and we also have a budget k, we have to find the maximum number of cars we can buy.

So, if the input is like [80, 20, 10, 30, 80], k = 85, then the output will be 3 as we can buy three cars with prices 20, 10, 40

To solve this, we will follow these steps −

• count := 0

• sort the list prices

• for i in range 0 to size of prices, do

  • if prices[i] <=k, then

    • k := k-prices[i]

    • count := count + 1

  • otherwise,

    • come out from the loop

• return count

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution:
   def solve(self, prices, k):
      count =0
      prices.sort()
      for i in range(len(prices)):
         if(prices[i]<=k):
            k = k-prices[i]
            count += 1
         else:
            break
      return count
ob = Solution()
p = [80, 20, 10, 30, 80]
print(ob.solve(p, 85))

Input

[80, 20, 10, 30, 80], 85

Output

3