8085 Program to convert an 8-bit binary to BCD

In this program we will see how to convert binary numbers to its BCD equivalent.

Problem Statement

A binary number is store dat location 800H. Convert the number into its BCD equivalent and store it to the memory location 8050H.

Discussion

Here we are taking a number from the memory, and initializing it as a counter. Now in each step of this counter we are incrementing the number by 1, and adjust the decimal value. By this process we are finding the BCD value of binary number or hexadecimal number.

We can use INR instruction to increment the counter in this case but this instruction will not affect carry flag, so for that reason we have used ADI 10H

Input

Address	Data
. . .	. . .
8000	34
. . .	. . .

Flow Diagram

Program

Address	HEX Codes	Labels	Mnemonics	Comments
F000	21, 00, 80		LXI H,8000H	Initialize memory pointer
F003	16, 00		MVI D,00H	Clear D- reg for Most significant Byte
F005	AF		XRA A	Clear Accumulator
F006	4E		MOV C, M	Get HEX data
F007	C6, 01	LOOP	ADI 01H	Count the number one by one
F009	27		DAA	Adjust for BCD count
F00A	D2, 0E, F0		JNC SKIP	Jump to SKIP
F00D	14		INR D	Increase D
F00E	0D	SKIP	DCR C	Decrease C register
F00F	C2, 07, F0		JNZ LOOP	Jump to LOOP
F012	6F		MOV L, A	Load the Least Significant Byte
F013	62		MOV H, D	Load the Most Significant Byte
F014	22, 50, 80		SHLD 8050H	Store the BCD
F017	76		HLT	Terminate the program