Type.GetInterface() Method in C#

The Type.GetInterface() method in C# is used to get a specific interface implemented or inherited by the current Type.

Syntax

Following is the syntax −

public Type GetInterface (string name);
public abstract Type GetInterface (string name, bool ignoreCase);

Example

Let us now see an example to implement the Type.GetInterface() method −

using System;
public class Demo {
   public static void Main(){
      Type type = typeof(double);
      Type myInterface = type.GetInterface("IFormattable");
      Console.WriteLine("Interface = "+myInterface);
   }
}

Output

This will produce the following output −

Interface = System.IFormattable

Example

Let us now see another example to implement the Type.GetInterface() method −

using System;
public class Demo {
   public static void Main(){
      Type type = typeof(float);
      Type myInterface = type.GetInterface("IFormattable",true);
      Console.WriteLine("Interface = "+myInterface);
   }
}

Output

This will produce the following output −

Interface = System.IFormattable

AmitDiwan

Updated on: 07-Nov-2019

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