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Sorting field value (FirstName) for MongoDB?
To sort values, use sort() in MongoDB. Let us first create a collection with documents −
> db.demo365.insertOne({"FirstName":"Chris"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e57d5b6d0ada61456dc936f")
}
> db.demo365.insertOne({"FirstName":"Adam"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e57d5bad0ada61456dc9370")
}
> db.demo365.insertOne({"FirstName":"John"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e57d5bed0ada61456dc9371")
}
> db.demo365.insertOne({"FirstName":"Bob"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e57d5c0d0ada61456dc9372")
}Display all documents from a collection with the help of find() method −
> db.demo365.find();
This will produce the following output −
{ "_id" : ObjectId("5e57d5b6d0ada61456dc936f"), "FirstName" : "Chris" }
{ "_id" : ObjectId("5e57d5bad0ada61456dc9370"), "FirstName" : "Adam" }
{ "_id" : ObjectId("5e57d5bed0ada61456dc9371"), "FirstName" : "John" }
{ "_id" : ObjectId("5e57d5c0d0ada61456dc9372"), "FirstName" : "Bob" }Following is the query for sorting −
> db.demo365.find().sort({"FirstName":1});This will produce the following output −
{ "_id" : ObjectId("5e57d5bad0ada61456dc9370"), "FirstName" : "Adam" }
{ "_id" : ObjectId("5e57d5c0d0ada61456dc9372"), "FirstName" : "Bob" }
{ "_id" : ObjectId("5e57d5b6d0ada61456dc936f"), "FirstName" : "Chris" }
{ "_id" : ObjectId("5e57d5bed0ada61456dc9371"), "FirstName" : "John" }
Updated on: 02-Apr-2020
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