Solve each of the following cryptarithms.
      3  7+A  B----     9   A  "

AcademicMathematicsNCERTClass 8

Given:

       $3  7$

$+$  $A  B$

      -----------

       $9   A$

To do:

We have to solve the given cryptarithms.

Solution:

$7+B=A$

$3+A=9$

If $A=6$ then $B=6-7=-1$ which is not possible.

This implies,

There is a carry of 1 in ten's place.

This implies,

$3+A+1=9$

$A=9-4=5$

There is a carry of 1 in ten's place.

$\Rightarrow 7+B=10+A=10+5=15$

Therefore,

$7+B=15$    

$B=15-7=8$

raja
Updated on 10-Oct-2022 13:19:20

Advertisements