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Remove all elements of a List that match the conditions defined by the predicate in C#
To remove all elements from a list that match the conditions defined by the predicate, the code is as follows −
Example
using System;
using System.Collections.Generic;
public class Demo {
private static bool demo(int i){
return (i == 500);
}
public static void Main(String[] args){
List<int> list = new List<int>();
list.Add(100);
list.Add(500);
list.Add(300);
list.Add(400);
list.Add(500);
list.Add(600);
list.Add(500);
Console.WriteLine("List elements...");
foreach (int i in list){
Console.WriteLine(i);
}
Console.WriteLine(" ");
list.RemoveAll(demo);
Console.WriteLine("List after removing elements 500...");
foreach (int i in list){
Console.WriteLine(i);
}
}
}Output
This will produce the following output −
List elements... 100 500 300 400 500 600 500 List after removing elements 500... 100 300 400 600
Example
Let us see another example −
using System;
using System.Collections.Generic;
public class Demo {
private static bool demo(int i){
return ((i % 10) == 0);
}
public static void Main(String[] args){
List<int> list = new List<int>();
list.Add(100);
list.Add(295);
list.Add(355);
list.Add(450);
list.Add(550);
Console.WriteLine("List elements...");
foreach (int i in list){
Console.WriteLine(i);
}
Console.WriteLine(" ");
list.RemoveAll(demo);
Console.WriteLine("List after removing elements...");
foreach (int i in list){
Console.WriteLine(i);
}
}
}Output
This will produce the following output −
List elements... 100 295 355 450 550 List after removing elements... 295 355
Updated on: 05-Dec-2019
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