Convert the Temperature

Convert the Temperature - Problem

Math Easy

You are given a non-negative floating point number rounded to two decimal places celsius, that denotes the temperature in Celsius.

You should convert Celsius into Kelvin and Fahrenheit and return it as an array ans = [kelvin, fahrenheit].

Return the array ans. Answers within 10^-5 of the actual answer will be accepted.

Note that:

Kelvin = Celsius + 273.15
Fahrenheit = Celsius * 1.80 + 32.00

Input & Output

Example 1 — Basic Case

$ Input: celsius = 36.50

› Output: [309.65, 97.70]

💡 Note: Kelvin = 36.50 + 273.15 = 309.65, Fahrenheit = 36.50 × 1.80 + 32.00 = 97.70

Example 2 — Zero Degrees

$ Input: celsius = 122.11

› Output: [395.26, 251.798]

💡 Note: Kelvin = 122.11 + 273.15 = 395.26, Fahrenheit = 122.11 × 1.80 + 32.00 = 251.798

Example 3 — Freezing Point

$ Input: celsius = 0.00

› Output: [273.15, 32.00]

💡 Note: At freezing point: Kelvin = 0 + 273.15 = 273.15, Fahrenheit = 0 × 1.80 + 32 = 32.00

Constraints

0 ≤ celsius ≤ 1000

Visualization

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Asked in

G Google 25 M Microsoft 20

This is a simple mathematical conversion problem. Apply the given formulas directly: Kelvin = Celsius + 273.15 and Fahrenheit = Celsius × 1.80 + 32.00. Time: O(1), Space: O(1)

Common Approaches

✓ Direct Mathematical Conversion

⏱️ Time: O(1) Space: O(1)

This is a straightforward mathematical problem. We simply apply the two given formulas: Kelvin = Celsius + 273.15 and Fahrenheit = Celsius * 1.80 + 32.00.

Direct Mathematical Conversion — Algorithm Steps

Read the Celsius temperature
Apply Kelvin formula: Celsius + 273.15
Apply Fahrenheit formula: Celsius * 1.80 + 32.00
Return both results as an array

Visualization

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Step-by-Step Walkthrough

Input

Read Celsius temperature

Apply Formulas

Calculate Kelvin and Fahrenheit using given formulas

Result

Return array with both converted values

Code -

solution.c — C

#include <stdio.h>
#include <stdlib.h>

void solution(double celsius, double* result) {
    result[0] = celsius + 273.15;  // Kelvin
    result[1] = celsius * 1.80 + 32.00;  // Fahrenheit
}

int main() {
    double celsius;
    scanf("%lf", &celsius);
    
    double result[2];
    solution(celsius, result);
    
    printf("[%f,%f]\n", result[0], result[1]);
    
    return 0;
}

Time & Space Complexity

Time Complexity

⏱️

O(1)

Only constant arithmetic operations regardless of input value

✓ Linear Growth

Space Complexity

O(1)

Only using a few variables to store results

✓ Linear Space

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Input & Output

Constraints

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Related Problems

Common Approaches

Direct Mathematical Conversion — Algorithm Steps

Visualization

Code -

Time & Space Complexity

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