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String Anagram Program in C
Implementation
Now, we shall see the actual implementation of the program −
#include <stdio.h> #include <string.h> int main (void) { char s1[] = "recitals"; char s2[] = "articles"; char temp; int i, j; int n = strlen(s1); int n1 = strlen(s2); // If both strings are of different length, then they are not anagrams if( n != n1) { printf("%s and %s are not anagrams! \n", s1, s2); return 0; } // lets sort both strings first − for (i = 0; i < n-1; i++) { for (j = i+1; j < n; j++) { if (s1[i] > s1[j]) { temp = s1[i]; s1[i] = s1[j]; s1[j] = temp; } if (s2[i] > s2[j]) { temp = s2[i]; s2[i] = s2[j]; s2[j] = temp; } } } // Compare both strings character by character for(i = 0; i<n; i++) { if(s1[i] != s2[i]) { printf("Strings are not anagrams! \n", s1, s2); return 0; } } printf("Strings are anagrams! \n"); return 0; }
Output
Output of this program should be −
Strings are anagrams!
string_programs_in_c.htm
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