Octal To Hexadecimal program in C
Implementation
Implementation of this algorithm is given below −
#include <stdio.h>
int string_length(char s[])
{
int i=0;
while(s[i]!='\0')
i++;
return i;
}
int octal2decimal(char n[])
{
int i,decimal,mul=0;
for(decimal=0,i=string_length(n)-1;i>=0;--i,mul+=3)
decimal+=(n[i]-48)*(1<<mul);
return decimal;
}
int main()
{ char n[] = "7";
char bits[100];
int i,j,d;
string_reverse(n);
for(i=j=0;n[i]!='\0';++i)
for(d=n[i]-48;d!=0;d/=2)
bits[j++]=d%2+48;
bits[j]='\0';
string_reverse(bits);
printf("Binary equivalent of %s is : %s\n", n, bits);
return 0;
}
Output
Output of the program should be −
Binary equivalent of 7 is : 111
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