Leap Year Program In C

Finding a year is leap or not is a bit tricky. We generally assume that if a year number is evenly divisible by 4 is leap year. But it is not the only case. A year is a leap year if −

• It is evenly divisible by 100

  • If it is divisible by 100, then it should also be divisible by 400

• Except this, all other years evenly divisible by 4 are leap years.

Let's see how to we can create a program to find if a year is leap or not.

Algorithm

Algorithm of this program is −

START
   Step 1 → Take integer variable year
   Step 2 → Assign value to the variable
   Step 3 → Check if year is divisible by 4 but not 100, DISPLAY "leap year"
   Step 4 → Check if year is divisible by 400, DISPLAY "leap year"
   Step 5 → Otherwise, DISPLAY "not leap year"
STOP

Flow Diagram

We can draw a flow diagram for this program as given below −

Pseudocode

The pseudocode of this algorithm sould be like this −

procedure leap_year()
   
   IF year%4 = 0 AND year%100 != 0 OR year%400 = 0
      PRINT year is leap
   ELSE
      PRINT year is not leap
   END IF

end procedure

Implementation

Implementation of this algorithm is given below −

#include <stdio.h>

int main() {
   int year;
   year = 2016;

   if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))
      printf("%d is a leap year", year);
   else
      printf("%d is not a leap year", year);

   return 0;
}

Output

Output of the program should be −

2016 is a leap year