Hexadacimal To Binary Program In C

Finding that a given number is even or odd, is a classic C program. We shall learn the use of conditional statement if-else in C.

Algorithm

Algorithm of this program is very easy −

START
      
   Step 1 → Take integer variable A
          
   Step 2 → Assign value to the variable

   Step 3 → Perform A modulo 2 and check result if output is 0
   
   Step 4 → If true print A is even
   
   Step 5 → If false print A is odd

STOP

Flow Diagram

We can draw a flow diagram for this program as given below −

Pseudocode

procedure even_odd()
   
   IF (number modulo 2) equals to 0
      PRINT number is even
   ELSE
      PRINT number is odd
   END IF

end procedure

Implementation

Implementation of this algorithm is given below −

#include <stdio.h>

int getHexValue(char d)
{
	if(d>='0' && d<='9') return d-48;
	else return d-'A'+10;
}

int main()
{   char n[50],temp[10];
	int i,j,v;
	
	printf("Enter a hexa number :");
	scanf("%s",n);
	
	printf("Binary equivalent is : ");
	for(j=0;n[j]!='\0';j++)
	{
	  v=getHexValue(n[j]);
	  
		for(i=0;i<4;i++) {
			temp[i]=v%2;
			v/=2;
		}
		for(--i;i>=0;i--)
			printf("%d",temp[i]);
	}
return 0;
}

Output

Output of the program should be −

24 is even
31 is odd

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