# Hexadacimal To Binary Program In C

Finding that a given number is even or odd, is a classic C program. We shall learn the use of conditional statement `if-else` in C.

## Algorithm

Algorithm of this program is very easy −

```START

Step 1 → Take integer variable A

Step 2 → Assign value to the variable

Step 3 → Perform A modulo 2 and check result if output is 0

Step 4 → If true print A is even

Step 5 → If false print A is odd

STOP
```

## Flow Diagram

We can draw a flow diagram for this program as given below −

## Pseudocode

```procedure even_odd()

IF (number modulo 2) equals to 0
PRINT number is even
ELSE
PRINT number is odd
END IF

end procedure
```

## Implementation

Implementation of this algorithm is given below −

```#include <stdio.h>

int getHexValue(char d)
{
if(d>='0' && d<='9') return d-48;
else return d-'A'+10;
}

int main()
{   char n[50],temp[10];
int i,j,v;

printf("Enter a hexa number :");
scanf("%s",n);

printf("Binary equivalent is : ");
for(j=0;n[j]!='\0';j++)
{
v=getHexValue(n[j]);

for(i=0;i<4;i++) {
temp[i]=v%2;
v/=2;
}
for(--i;i>=0;i--)
printf("%d",temp[i]);
}
return 0;
}

```

## Output

Output of the program should be −

```24 is even
31 is odd
```