java.time.Duration.minusNanos() Method Example

Description

The java.time.Duration.minusNanos(long nanosToSubtract) method returns a copy of this duration with the specified duration in nanoseconds subtracted.

Declaration

Following is the declaration for java.time.Duration.minusNanos(long nanosToSubtract) method.

public Duration minusNanos(long nanosToSubtract)

Parameters

nanosToSubtract − the nanoseconds to subtract, positive or negative.

Return Value

a Duration based on this duration with the specified nanoseconds subtracted, not null.

Exception

ArithmeticException − if numeric overflow occurs.

Example

The following example shows the usage of java.time.Duration.minusNanos(long nanosToSubtract) method.

package com.tutorialspoint;

import java.time.Duration;

public class DurationDemo {
   public static void main(String[] args) {

      Duration duration = Duration.ofSeconds(5);
      Duration duration1 = duration.minusNanos(3000);
      Duration duration2 = duration.minusNanos(4000);
      System.out.println(duration1.getNano());
      System.out.println(duration2.getNano());
   }
}

Let us compile and run the above program, this will produce the following result −

999997000
999996000