JavaScript Determine the array having majority element and return TRUE if its in the same array

We are required to write a JavaScript function that takes in an array of numbers with repetitive values and returns the number that appears for more than (n/2) number of times where n is the length of the array. If there is no such element in the array, our function should return false

Let's write the code for this function −

Example

const arr = [12, 5, 67, 12, 4, 12, 4, 12, 6, 12, 12];
const arr1 = [3, 565, 7, 23, 87, 23, 3, 65, 1, 3, 6, 7];
const findMajority = arr => {
   let maxChar = -Infinity, maxCount = 1;
   // this loop determines the possible candidates for majorityElement
   for(let i = 0; i < arr.length; i++){
      if(maxChar !== arr[i]){
         if(maxCount === 1){
            maxChar = arr[i];
         } 0else {
            maxCount--;
      };
      } else {
         maxCount++;
      };
   };
   // this loop actually checks for the candidate to be the majority
   element
   const count = arr.reduce((acc, val) => maxChar===val ? ++acc : acc, 0);
   return count > arr.length / 2;
};
console.log(findMajority(arr));
console.log(findMajority(arr1));

Output

The output in the console will be −

true
false

AmitDiwan

e

Updated on: 31-Aug-2020

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