# Java.lang.StrictMath.log10() Method

## Description

The java.lang.StrictMath.log10() method returns the base 10 logarithm of a double value.It include some cases −

• If the argument is NaN or less than zero, then the result is NaN.
• If the argument is positive infinity, then the result is positive infinity.
• If the argument is positive zero or negative zero, then the result is negative infinity.
• If the argument is equal to 10n for integer n, then the result is n.

## Declaration

Following is the declaration for java.lang.StrictMath.log10() method

```public static double log10(double a)
```

## Parameters

a − This is the value.

## Return Value

This method returns the base 10 logarithm of a.

NA

## Example

The following example shows the usage of java.lang.StrictMath.log10() method.

```package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

public static void main(String[] args) {

double d1 = 0.0 , d2 = 1000.0 , d3 = (1.0/0.0), d4 = 1;

// returns natural logarithm (base 10) of a double value.
double log10Value = StrictMath.log10(d1);
System.out.println("Log " + d1 + " with base 10 = " + log10Value);

// if the argument is equal to 10n for integer n, it returns n.
log10Value = StrictMath.log10(d2);
System.out.println("Log " + d2 + " with base 10 = " + log10Value);

log10Value = StrictMath.log10(d3);
System.out.println("Log " + d3 + " with base 10 = " + log10Value);

log10Value = StrictMath.log10(d4);
System.out.println("Log " + d4 + " with base 10 = " + log10Value);
}
}
```

Let us compile and run the above program, this will produce the following result −

```Log 0.0 with base 10 = -Infinity
Log 1000.0 with base 10 = 3.0