Java - StrictMath log10(double) Method

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Description

The Java StrictMath log10(double a) returns the base 10 logarithm of a double value. Special cases:

• If the argument is NaN or less than zero, then the result is NaN.
• If the argument is positive infinity, then the result is positive infinity.
• If the argument is positive zero or negative zero, then the result is negative infinity.
• If the argument is equal to 10n for integer n, then the result is n.

Declaration

Following is the declaration for java.lang.StrictMath.log10() method

public static double log10(double a)

Parameters

a − a value

Return Value

This method returns the base 10 logarithm of a.

Exception

NA

Getting Log10 of a Positive Double Value Example

The following example shows the usage of StrictMath log10() method.

package com.tutorialspoint;

public class StrictMathDemo {

   public static void main(String[] args) {

      // get a double number
      double x = 10.7;

      // print the log10 of the number
      System.out.println("StrictMath.log10(" + x + ")=" + StrictMath.log10(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

StrictMath.log10(10.7)=1.0293837776852097

Getting Log10 of a Zero Double Value Example

The following example shows the usage of StrictMath log10() method of zero value.

package com.tutorialspoint;

public class StrictMathDemo {

   public static void main(String[] args) {

      // get a double number
      double x = 0.0;

      // print the log10 of the number
      System.out.println("StrictMath.log10(" + x + ")=" + StrictMath.log10(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

StrictMath.log10(0.0)=-Infinity

Getting Log10 of a Negative Double Value Example

The following example shows the usage of StrictMath log10() method of a negative number.

package com.tutorialspoint;

public class StrictMathDemo {

   public static void main(String[] args) {

      // get a double number
      double x = -10.7;

      // print the log10 of the number
      System.out.println("StrictMath.log10(" + x + ")=" + StrictMath.log10(x));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

StrictMath.log10(-10.7)=NaN