Java.lang.StrictMath.exp() Method

Description

The java.lang.StrictMath.exp() method returns Euler's number e raised to the power of a double value.It include these cases −

• If the argument is NaN, then the result is NaN.
• If the argument is positive infinity, then the result is positive infinity.
• If the argument is negative infinity, then the result is positive zero.

Declaration

Following is the declaration for java.lang.StrictMath.exp() method

```public static double exp(double a)
```

Parameters

a − This is the exponent to raise e to.

Return Value

This method returns the value ea, where e is the base of the natural logarithms.

NA

Example

The following example shows the usage of java.lang.StrictMath.exp() method.

```package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

public static void main(String[] args) {

double d1 = 0.0 , d2 = -0.0, d3 = (1.0/0.0), d4 = 5;

// returns Euler's number e raised to the power positive 0
double eulerValue = StrictMath.exp(d1);
System.out.println("Euler value of d1 = " + eulerValue);

// returns Euler's number e raised to the power negative 0
eulerValue = StrictMath.exp(d2);
System.out.println("Euler value of d2 = " + eulerValue);

// returns Euler's number e raised to the power infinity
eulerValue = StrictMath.exp(d3);
System.out.println("Euler value of d3 = " + eulerValue);

// returns Euler's number e raised to the power 5
eulerValue = StrictMath.exp(d4);
System.out.println("Euler value of d4 = " + eulerValue);
}
}
```

Let us compile and run the above program, this will produce the following result −

```Euler value of d1 = 1.0
Euler value of d2 = 1.0
Euler value of d3 = Infinity
Euler value of d4 = 148.4131591025766
```
java_lang_strictmath.htm