# Java.lang.StrictMath.cbrt() Method

## Description

The java.lang.StrictMath.cbrt() method returns the cube root of a double value. For positive finite x, cbrt(-x) == -cbrt(x); that is, the cube root of a negative value is the negative of the cube root of that value's magnitude.This include these cases −

• If the argument is NaN, then the result is NaN.
• If the argument is infinite, then the result is an infinity with the same sign as the argument.
• If the argument is zero, then the result is a zero with the same sign as the argument.

## Declaration

Following is the declaration for java.lang.StrictMath.cbrt() method

```public static double cbrt(double a)
```

## Parameters

a − This is the double value

## Return Value

This method returns the cube root of a.

NA

## Example

The following example shows the usage of java.lang.StrictMath.cbrt() method.

```package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

public static void main(String[] args) {

double d1 = 8.05 , d2 = 729, d3 = 0;

// returns the cube root of a double value
double cbrtValue = StrictMath.cbrt(d1);
System.out.println("Cube root of " + d1 + " = " + cbrtValue);

cbrtValue = StrictMath.cbrt(d2);
System.out.println("Cube root of " + d2 + " = " + cbrtValue);

cbrtValue = StrictMath.cbrt(d3);
System.out.println("Cube root of " + d3 + " = " + cbrtValue);
}
}
```

Let us compile and run the above program, this will produce the following result −

```Cube root of 8.05 = 2.0041580161269152
Cube root of 729 = 9.0
Cube root of 0 = 0.0
```
java_lang_strictmath.htm