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Java.lang.StrictMath.abs() Method
Description
The java.lang.StrictMath.abs(float a) method returns the absolute value of a float value. If the argument is not negative, the argument is returned. If the argument is negative, the negation of the argument is returned. It includes some cases:
- If the argument is positive zero or negative zero, the result is positive zero.
- If the argument is infinite, the result is positive infinity.
- If the argument is NaN, the result is NaN.
Declaration
Following is the declaration for java.lang.StrictMath.abs() method
public static float abs(float a)
Parameters
a − This is the argument whose absolute value is to be determined.
Return Value
This method returns the absolute value of a float value.
Exception
NA
Example
The following example shows the usage of java.lang.StrictMath.abs() method.
package com.tutorialspoint; import java.lang.*; public class StrictMathDemo { public static void main(String[] args) { float f1 = 78 , f2 = -9; // returns the absolute value of positive float value float fAbsValue = StrictMath.abs(f1); System.out.println("absolute value of " + f1 + " = " + fAbsValue); // returns the absolute value of negative float value fAbsValue = StrictMath.abs(f2); System.out.println("absolute value of " + f2 + " = " + fAbsValue); } }
Let us compile and run the above program, this will produce the following result −
absolute value of 78.0 = 78.0 absolute value of -9.0 = 9.0
java_lang_strictmath.htm
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