Java.lang.StrictMath.abs() Method



Description

The java.lang.StrictMath.abs(double a) method returns the absolute value of a double value. If the argument is not negative, the argument is returned. If the argument is negative, the negation of the argument is returned. It include some cases:

  • If the argument is positive zero or negative zero, the result is positive zero.
  • If the argument is infinite, the result is positive infinity.
  • If the argument is NaN, the result is NaN.

Declaration

Following is the declaration for java.lang.StrictMath.abs() method

public static double abs(double a)

Parameters

  • a − This is the argument whose absolute value is to be determined.

Return Value

This method returns the absolute value of a double value.

Exception

NA

Example

The following example shows the usage of java.lang.StrictMath.abs() method.

package com.tutorialspoint;

import java.lang.*;

public class StrictMathDemo {

   public static void main(String[] args) {

      double d1 = 1245.9 , d2 = -987.8;
  
      // returns the absolute value of positive double value
      double dAbsValue = StrictMath.abs(d1); 
      System.out.println("absolute value of " + d1 + " = " + dAbsValue);

      // returns the absolute value of negative double value
      dAbsValue = StrictMath.abs(d2); 
      System.out.println("absolute value of " + d2 + " = " + dAbsValue);
   }
} 

Let us compile and run the above program, this will produce the following result −

absolute value of 1245.9 = 1245.9
absolute value of -987.8 = 987.8
java_lang_strictmath.htm
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