Java - Math IEEEremainder(double x, double y) method

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Description

The Java Math IEEEremainder(double f1, double f2) returns Computes the remainder operation on two arguments as prescribed by the IEEE 754 standard. The remainder value is mathematically equal to f1 - f2 x n, where n is the mathematical integer closest to the exact mathematical value of the quotient f1/f2, and if two mathematical integers are equally close to f1/f2, then n is the integer that is even. If the remainder is zero, its sign is the same as the sign of the first argument. Special cases −

• If either argument is NaN, or the first argument is infinite, or the second argument is positive zero or negative zero, then the result is NaN.

• If the first argument is finite and the second argument is infinite, then the result is the same as the first argument.

Declaration

Following is the declaration for java.lang.Math.IEEEremainder() method

public static double IEEEremainder(double f1, double f2)

Parameters

• f1 − the dividend.

• f2 − the divisor.

Return Value

This method returns the remainder when f1 is divided by f2.

Exception

NA

Example 1

The following example shows the usage of Math IEEEremainder() method.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get two double numbers
      double x = 60984.1;
      double y = -497.99;
   
      // call IEEEremainder and print the result
      System.out.println("Math.IEEEremainder(" + x + "," + y + ")=" + Math.IEEEremainder(x, y));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.IEEEremainder(60984.1,-497.99)=229.31999999999744

Example 2

The following example shows the usage of Math IEEEremainder() method of zero value.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get two double numbers
      double x = 0.0;
      double y = -0.0;
   
      // call IEEEremainder and print the result
      System.out.println("Math.IEEEremainder(" + x + "," + y + ")=" + Math.IEEEremainder(x, y));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.IEEEremainder(0.0,-0.0)=NaN

Example 3

The following example shows the usage of Math IEEEremainder() method of a 1 value.

package com.tutorialspoint;
public class MathDemo {
   public static void main(String[] args) {

      // get two double numbers
      double x = 1.0;
      double y = -1.0;
   
      // call hypot and print the result
      System.out.println("Math.IEEEremainder(" + x + "," + y + ")=" + Math.IEEEremainder(x, y));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Math.IEEEremainder(1.0,-1.0)=0.0