Java.lang.Math.hypot() Method

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Description

The java.lang.Math.hypot(double x, double y) returns sqrt(x² +y²) without intermediate overflow or underflow. Special cases:

• If either argument is infinite, then the result is positive infinity.

• If either argument is NaN and neither argument is infinite, then the result is NaN.

Declaration

Following is the declaration for java.lang.Math.hypot() method

public static double hypot(double x, double y)

Parameters

• x − a value

• y − a value

Return Value

This method returns sqrt(x² +y²) without intermediate overflow or underflow

Exception

NA

Example

The following example shows the usage of lang.Math.hypot() method.

package com.tutorialspoint;

import java.lang.*;

public class MathDemo {

   public static void main(String[] args) {

      // get two double numbers
      double x = 60984.1;
      double y = -497.99;
   
      // call hypot and print the result
      System.out.println("Math.hypot(" + x + "," + y + ")=" + Math.hypot(x, y));
   }
}

Let us compile and run the above program, this will produce the following result −

Math.hypot(60984.1, -497.99)=60986.133234122164