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Java.lang.Math.exp() Method
Description
The java.lang.Math.exp(double a) returns Euler's number e raised to the power of a double value. Special cases:
If the argument is NaN, the result is NaN.
If the argument is positive infinity, then the result is positive infinity.
If the argument is negative infinity, then the result is positive zero.
The computed result must be within 1 ulp of the exact result. Results must be semi-monotonic.
Declaration
Following is the declaration for java.lang.Math.exp() method
public static double exp(double a)
Parameters
a − the exponent to raise e to.
Return Value
This method returns the value ea, where e is the base of the natural logarithms.
Exception
NA
Example
The following example shows the usage of lang.Math.exp() method.
package com.tutorialspoint; import java.lang.*; public class MathDemo { public static void main(String[] args) { // get two double numbers double x = 5; double y = 0.5; // print e raised at x and y System.out.println("Math.exp(" + x + ")=" + Math.exp(x)); System.out.println("Math.exp(" + y + ")=" + Math.exp(y)); } }
Let us compile and run the above program, this will produce the following result −
Math.exp(5)=148.4131591025766 Math.exp(0.5)=1.6487212707001282
java_lang_math.htm
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