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Java.lang.Math.ceil() Method
Description
The java.lang.Math.ceil(double a) returns the smallest (closest to negative infinity) double value that is greater than or equal to the argument and is equal to a mathematical integer. Special cases −
If the argument value is already equal to a mathematical integer, then the result is the same as the argument.
If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.
If the argument value is less than zero but greater than -1.0, then the result is negative zero.
Note that the value of Math.ceil(x) is exactly the value of -Math.floor(-x).
Declaration
Following is the declaration for java.lang.Math.ceil() method
public static double ceil(double a)
Parameters
a − a value.
Return Value
This method returns the smallest (closest to negative infinity) floating-point value that is greater than or equal to the argument and is equal to a mathematical integer.
Exception
NA
Example
The following example shows the usage of lang.Math.ceil() method.
package com.tutorialspoint; import java.lang.*; public class MathDemo { public static void main(String[] args) { // get two double numbers double x = 125.9; double y = 0.4873; // call ceal for these these numbers System.out.println("Math.ceil(" + x + ")=" + Math.ceil(x)); System.out.println("Math.ceil(" + y + ")=" + Math.ceil(y)); System.out.println("Math.ceil(-0.65)=" + Math.ceil(-0.65)); } }
Let us compile and run the above program, this will produce the following result −
Math.ceil(125.9)=126.0 Math.ceil(0.4873)=1.0 Math.ceil(-0.65)=-0.0