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Java.lang.Long.numberOfTrailingZeros() Method
Description
The java.lang.Long.numberOfTrailingZeros() method returns the number of zero bits following the lowest-order ("rightmost") one-bit in the two's complement binary representation of the specified long value. It returns 64 if the specified value has no one-bits in its two's complement representation, in other words if it is equal to zero.
Declaration
Following is the declaration for java.lang.Long.numberOfTrailingZeros() method
public static int numberOfTrailingZeros(long i)
Parameters
i − This is the long value.
Return Value
This method returns the number of zero bits following the lowest-order ("rightmost") one-bit in the two's complement binary representation of the specified long value, or 64 if the value is equal to zero.
Exception
NA
Example
The following example shows the usage of java.lang.Long.numberOfTrailingZeros() method.
package com.tutorialspoint; import java.lang.*; public class LongDemo { public static void main(String[] args) { long l = 210; System.out.println("Number = " + l); /* returns the string representation of the unsigned long value represented by the argument in binary (base 2) */ System.out.println("Binary = " + Long.toBinaryString(l)); /* returns a long value with at most a single one-bit, in the position of the lowest-order ("rightmost") one-bit in the specified int value.*/ System.out.println("Lowest one bit = " + Long.lowestOneBit(l)); /*returns the number of zero bits preceding the highest-order ("leftmost")one-bit */ System.out.print("Number of leading zeros = "); System.out.println(Long.numberOfLeadingZeros(l)); /* returns the number of zero bits following the lowest-order ("rightmost") one-bit */ System.out.print("Number of trailing zeros = "); System.out.println(Long.numberOfTrailingZeros(l)); } }
Let us compile and run the above program, this will produce the following result −
Number = 210 Binary = 11010010 Lowest one bit = 2 Number of leading zeros = 56 Number of trailing zeros = 1