Java.lang.Long.lowestOneBit() Method


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Description

The java.lang.Long.lowestOneBit() method returns a long value with at most a single one-bit, in the position of the lowest-order ("rightmost") one-bit in the specified long value. It returns zero if the specified value has no one-bits in its two's complement binary representation, that is, if it is equal to zero.

Declaration

Following is the declaration for java.lang.Long.lowestOneBit() method

public static long lowestOneBit(long i)

Parameters

i − This is the long value.

Return Value

This method returns long value with a single one-bit, in the position of the lowest-order one-bit in the specified value, or zero if the specified value is itself equal to zero.

Exception

NA

Example

The following example shows the usage of java.lang.Long.lowestOneBit() method.

Live Demo
package com.tutorialspoint;

import java.lang.*;

public class LongDemo {

   public static void main(String[] args) {

      long l = 210;
      System.out.println("Number = " + l);

      /* returns the string representation of the unsigned long value 
         represented by the argument in binary (base 2) */
      System.out.println("Binary = " + Long.toBinaryString(l));

      /* returns a long value with at most a single one-bit, in the position
         of the lowest-order ("rightmost") one-bit in the specified int value.*/
      System.out.println("Lowest one bit = " + Long.lowestOneBit(l));
   }
}  

Let us compile and run the above program, this will produce the following result −

Number = 210
Binary = 11010010
Lowest one bit = 2

java_lang_long.htm

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