Java.lang.Integer.numberOfTrailingZeros() Method

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Description

The java.lang.Integer.numberOfTrailingZeros() returns the number of zero bits following the lowest-order ("rightmost") one-bit in the two's complement binary representation of the specified int value.

It returns 32 if the specified value has no one-bits in its two's complement representation, in other words if it is equal to zero.

Declaration

Following is the declaration for java.lang.Integer.numberOfTrailingZeros() method

public static int numberOfTrailingZeros(int i)

Parameters

i − This is the int value.

Return Value

This method returns the number of zero bits preceding the highest-order ("leftmost") one-bit in the two's complement binary representation of the specified int value, or 32 if the value is equal to zero.

Exception

NA

Example

The following example shows the usage of java.lang.Integer.numberOfTrailingZeros() method.

package com.tutorialspoint;

import java.lang.*;

public class IntegerDemo {

   public static void main(String[] args) {

      int i = 170;
      System.out.println("Number = " + i);

      /* returns the string representation of the unsigned integer value 
         represented by the argument in binary (base 2) */
      System.out.println("Binary = " + Integer.toBinaryString(i));

      // returns the number of one-bits 
      System.out.println("Number of one bits = " + Integer.bitCount(i));

      /* returns an int value with at most a single one-bit, in the position 
         of the highest-order ("leftmost") one-bit in the specified int value */
      System.out.println("Highest one bit = " + Integer.highestOneBit(i));

      /* returns an int value with at most a single one-bit, in the position
         of the lowest-order ("rightmost") one-bit in the specified int value.*/
      System.out.println("Lowest one bit = " + Integer.lowestOneBit(i));

      /*returns the number of zero bits preceding the highest-order 
         ("leftmost")one-bit */
      System.out.print("Number of leading zeros = ");
      System.out.println(Integer.numberOfLeadingZeros(i));

      /* returns the number of zero bits following the lowest-order 
         ("rightmost") one-bit */
      System.out.print("Number of trailing zeros = ");
      System.out.println(Integer.numberOfTrailingZeros(i));  
   }
}

Let us compile and run the above program, this will produce the following result −

Number = 170
Binary = 10101010
Number of one bits = 4
Highest one bit = 128
Lowest one bit = 2
Number of leading zeros = 24
Number of trailing zeros = 1