Java - Integer lowestOneBit() method

Description

The Java Integer lowestOneBit() method returns an int value with at most a single one-bit, in the position of the lowest-order ("rightmost") one-bit in the specified int value. It returns zero if the specified value has no one-bits in its two's complement binary representation, that is, if it is equal to zero.

Declaration

Following is the declaration for java.lang.Integer.lowestOneBit() method

public static int lowestOneBit(int i)

Parameters

i − This is the int value.

Return Value

This method returns an int value with a single one-bit, in the position of the lowest-order one-bit in the specified value, or zero if the specified value is itself equal to zero.

Exception

NA

Example 1

The following example shows the usage of Integer lowestOneBit() method to get an int value with at most a single one-bit in the position of the lowest-order. We've created a int variable and assigned it a positive int value. Then using toBinaryString() method, we're printing the binary format of the value. Using bitCount(), we're printing the one bits count and then value of lowest one bit is printed using lowestOneBit() method.

package com.tutorialspoint;
public class IntegerDemo {
   public static void main(String[] args) {
      int i = 170;
      System.out.println("Number = " + i);

      /* returns the string representation of the unsigned integer value 
         represented by the argument in binary (base 2) */
      System.out.println("Binary = " + Integer.toBinaryString(i));

      // returns the number of one-bits 
      System.out.println("Number of one bits = " + Integer.bitCount(i));

      /* returns an int value with at most a single one-bit, in the position 
         of the lowest-order ("rightmost") one-bit in the specified int value */ 
      System.out.println("Lowest one bit = " + Integer.lowestOneBit(i));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Number = 170
Binary = 10101010
Number of one bits = 4
Lowest one bit = 2

Example 2

The following example shows the usage of Integer lowestOneBit() method to get an int value with at most a single one-bit in the position of the lowest-order. We've created a int variable and assigned it a negative int value. Then using toBinaryString() method, we're printing the binary format of the value. Using bitCount(), we're printing the one bits count and then value of lowest one bit is printed using lowestOneBit() method.

package com.tutorialspoint;
public class IntegerDemo {
   public static void main(String[] args) {
      int i = -170;
      System.out.println("Number = " + i);

      /* returns the string representation of the unsigned integer value 
         represented by the argument in binary (base 2) */
      System.out.println("Binary = " + Integer.toBinaryString(i));

      // returns the number of one-bits 
      System.out.println("Number of one bits = " + Integer.bitCount(i));

      /* returns an int value with at most a single one-bit, in the position 
         of the lowest-order ("rightmost") one-bit in the specified int value */ 
      System.out.println("Lowest one bit = " + Integer.lowestOneBit(i));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Number = -170
Binary = 11111111111111111111111101010110
Number of one bits = 28
Lowest one bit = 2

Example 3

The following example shows the usage of Integer lowestOneBit() method to get an int value with at most a single one-bit in the position of the lowest-order. We've created a int variable and assigned it a positive int value. Then using toBinaryString() method, we're printing the binary format of the value. Using bitCount(), we're printing the one bits count and then value of lowest one bit is printed using lowestOneBit() method.

package com.tutorialspoint;
public class IntegerDemo {
   public static void main(String[] args) {
      int i = 0;
      System.out.println("Number = " + i);

      /* returns the string representation of the unsigned integer value 
         represented by the argument in binary (base 2) */
      System.out.println("Binary = " + Integer.toBinaryString(i));

      // returns the number of one-bits 
      System.out.println("Number of one bits = " + Integer.bitCount(i));

      /* returns an int value with at most a single one-bit, in the position 
         of the lowest-order ("rightmost") one-bit in the specified int value */ 
      System.out.println("Lowest one bit = " + Integer.lowestOneBit(i));
   }
}

Output

Let us compile and run the above program, this will produce the following result −

Number = 0
Binary = 0
Number of one bits = 0
Lowest one bit = 0
java_lang_integer.htm
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