Java.lang.Integer.highestOneBit() Method

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Description

The java.lang.Integer.highestOneBit() method returns an int value with at most a single one-bit, in the position of the highest-order ("leftmost") one-bit in the specified int value. It returns zero if the specified value has no one-bits in its two's complement binary representation, that is, if it is equal to zero.

Declaration

Following is the declaration for java.lang.Integer.highestOneBit() method

public static int highestOneBit(int i)

Parameters

i − This is the int value.

Return Value

This method returns an int value with a single one-bit, in the position of the highest-order one-bit in the specified value, or zero if the specified value is itself equal to zero.

Exception

NA

Example

The following example shows the usage of java.lang.Integer.highestOneBit() method.

package com.tutorialspoint;

import java.lang.*;

public class IntegerDemo {

   public static void main(String[] args) {

      int i = 170;
      System.out.println("Number = " + i);

      /* returns the string representation of the unsigned integer value 
         represented by the argument in binary (base 2) */
      System.out.println("Binary = " + Integer.toBinaryString(i));

      // returns the number of one-bits 
      System.out.println("Number of one bits = " + Integer.bitCount(i));

      /* returns an int value with at most a single one-bit, in the position 
         of the highest-order ("leftmost") one-bit in the specified int value */ 
      System.out.println("Highest one bit = " + Integer.highestOneBit(i));
   }
}

Let us compile and run the above program, this will produce the following result −

Number = 170
Binary = 10101010
Number of one bits = 4
Highest one bit = 128