Java.lang.Double.longBitsToDouble() Method

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Description

The java.lang.Double.longBitsToDouble() method returns the double value corresponding to a given bit representation. The argument is considered to be a representation of a floating-point value according to the IEEE 754 floating-point "double format" bit layout.It includes the following important points −

• If the argument is 0x7ff0000000000000L, the result is positive infinity.
• If the argument is 0xfff0000000000000L, the result is negative infinity.

Declaration

Following is the declaration for java.lang.Double.longBitsToDouble() method

public static double longBitsToDouble(long bits)

Parameters

bits − This is any long integer.

Return Value

This method returns the double floating-point value with the same bit pattern.

Exception

NA

Example

The following example shows the usage of java.lang.Double.longBitsToDouble() method.

package com.tutorialspoint;

import java.lang.*;

public class DoubleDemo {

   public static void main(String[] args) {

      Double d = new Double("15.30");
   
      /* returns the double value corresponding to a given bit representation */
      System.out.println(d.longBitsToDouble(6757689));
      System.out.println(d.longBitsToDouble(0x7ff0000000000000L));  
      System.out.println(d.longBitsToDouble(0xfff0000000000000L));  
   }
} 

Let us compile and run the above program, this will produce the following result −

3.338742E-317
Infinity
-Infinity