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Java.lang.Double.doubleToRawLongBits() Method
Description
The java.lang.Double.doubleToRawLongBits() method returns a representation of the specified floating-point value according to the IEEE 754 floating-point "double format" bit layout, preserving Not-a-Number (NaN) values.It includes the following important points −
- If the argument is positive infinity, the result is 0x7ff0000000000000L.
- If the argument is negative infinity, the result is 0xfff0000000000000L.
- If the argument is NaN, the result is the long integer representing the actual NaN value. Different from doubleToLongBits method, doubleToRawLongBits does not collapse all the bit patterns encoding a NaN to a single "canonical" NaN value.
Declaration
Following is the declaration for java.lang.Double.doubleToRawLongBits() method
public static long doubleToRawLongBits(double value)
Parameters
value − This is a double precision floating-point number.
Return Value
This method returns the bits that represent the floating-point number.
Exception
NA
Example
The following example shows the usage of java.lang.Double.doubleToRawLongBits() method.
package com.tutorialspoint; import java.lang.*; public class DoubleDemo { public static void main(String[] args) { Double d = new Double("10.50"); //returns the bits that represent the floating-point number System.out.println("Value = " + d.doubleToRawLongBits(2.5d)); } }
Let us compile and run the above program, this will produce the following result −
Value = 4612811918334230528
java_lang_double.htm
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