Java.lang.Byte.equals() Method


The java.lang.Byte.equals(Object obj) compares this object to the specified object. The result is true if and only if the argument is not null and is a Byte object that contains the same byte value as this object.


Following is the declaration for java.lang.Byte.equals() method

public boolean equals(Object obj)


equals in class Object


obj − the object to compare with

Return Value

This method returns true if the objects are the same, false otherwise.




The following example shows the usage of lang.Byte.equals() method.

package com.tutorialspoint;

import java.lang.*;

public class ByteDemo {

   public static void main(String[] args) {

      // create 2 Byte objects b1, b2
      Byte b1, b2;

      // create 2 boolean primitives bool1, bool2
      boolean bool1, bool2;

      // assign values to b1, b2
      b1 = new Byte("100");
      b2 = new Byte("100");

      // compare b1 and b2 and assign result to bool1
      bool1 = b1.equals(b2);

       *  compare b1 with object 100 and assign result to bool2, it
       *  returns false as 100 is not a Byte object
      bool2 = b1.equals("100");

      String str1 = b1 + " equals " + b2 + " is " + bool1;
      String str2 = b1 + " equals object value 100 is " + bool2;

      // print bool1, bool2 values
      System.out.println( str1 );
      System.out.println( str2 );

Let us compile and run the above program, this will produce the following result −

100 equals 100 is true
100 equals object value 100 is false