Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Java Program to subtract long integers and check for overflow
To check for Long overflow, we need to check the Long.MAX_VALUE with the subtracted long result. Here, Long.MAX_VALUE is the maximum value of Long type in Java.
Let us see an example wherein long integers are subtracted and if the result is still more than the Long.MAX_VALUE, then an exception is thrown −
The following is an example showing how to check for Long overflow −
Example
public class Demo {
public static void main(String[] args) {
long val1 = 70123;
long val2 = 10567;
System.out.println("Value1: "+val1);
System.out.println("Value2: "+val2);
long diff = val1 - val2;
if (diff > Long.MAX_VALUE) {
throw new ArithmeticException("Overflow!");
}
// displaying subtraction
System.out.println("Subtraction Result: "+diff);
}
}Output
Value1: 70123 Value2: 10567 Subtraction Result: 59556
In the above example, we have taken the following two integers −
long val1 = 70123; long val2 = 10567;
Now we will perform subtraction −
long diff = val1 - val2;
If the result is still more than the maximum value, then an exception is thrown −
If (diff > Long.MAX_VALUE) {
throw new ArithmeticException("Overflow!");
}
Updated on: 30-Jul-2019
543 Views
Advertisements