Java Program to subtract long integers and check for overflow

To check for Long overflow, we need to check the Long.MAX_VALUE with the subtracted long result. Here, Long.MAX_VALUE is the maximum value of Long type in Java.

Let us see an example wherein long integers are subtracted and if the result is still more than the Long.MAX_VALUE, then an exception is thrown −

The following is an example showing how to check for Long overflow −

Example

 Live Demo

public class Demo {
   public static void main(String[] args) {
      long val1 = 70123;
      long val2 = 10567;
      System.out.println("Value1: "+val1);
      System.out.println("Value2: "+val2);
      long diff = val1 - val2;
      if (diff > Long.MAX_VALUE) {
         throw new ArithmeticException("Overflow!");
      }
      // displaying subtraction
      System.out.println("Subtraction Result: "+diff);
   }
}

Output

Value1: 70123
Value2: 10567
Subtraction Result: 59556

In the above example, we have taken the following two integers −

long val1 = 70123;
long val2 = 10567;

Now we will perform subtraction −

long diff = val1 - val2;

If the result is still more than the maximum value, then an exception is thrown −

If (diff > Long.MAX_VALUE) {
   throw new ArithmeticException("Overflow!");
}

Samual Sam

Published on 26-Dec-2018 10:35:25

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