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Java Program to subtract long integers and check for overflow
To check for Long overflow, we need to check the Long.MAX_VALUE with the subtracted long result. Here, Long.MAX_VALUE is the maximum value of Long type in Java.
Let us see an example wherein long integers are subtracted and if the result is still more than the Long.MAX_VALUE, then an exception is thrown −
The following is an example showing how to check for Long overflow −
Example
public class Demo { public static void main(String[] args) { long val1 = 70123; long val2 = 10567; System.out.println("Value1: "+val1); System.out.println("Value2: "+val2); long diff = val1 - val2; if (diff > Long.MAX_VALUE) { throw new ArithmeticException("Overflow!"); } // displaying subtraction System.out.println("Subtraction Result: "+diff); } }
Output
Value1: 70123 Value2: 10567 Subtraction Result: 59556
In the above example, we have taken the following two integers −
long val1 = 70123; long val2 = 10567;
Now we will perform subtraction −
long diff = val1 - val2;
If the result is still more than the maximum value, then an exception is thrown −
If (diff > Long.MAX_VALUE) { throw new ArithmeticException("Overflow!"); }
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