Is $ \frac{8}{9} $ the multiplicative inverse of $ -1 \frac{1}{8} $ ? Why or why not?

AcademicMathematicsNCERTClass 8

To do: 

We have to find whether \( \frac{8}{9} \) is the multiplicative inverse of \( -1 \frac{1}{8} \).

Solution:

$-1\frac{1}{8} =-(1\frac{1}{8})$

$=-(\frac{1\times8+1}{8})$

$=-\frac{9}{8}$

We know that,

The multiplicative inverse of $\frac{a}{b}$ is $\frac{b}{a}$ 

Therefore,

The multiplicative inverse of $\frac{-9}{8}$ is $\frac{8}{-9}=\frac{-8}{9}$ 

$\frac{-8}{9}≠\frac{8}{9}$

Hence, $\frac{8}{9}$ is not the multiplicative inverse of $-1\frac{1}{8}$.

raja
Updated on 10-Oct-2022 13:47:38

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