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How to match one character in MySQL in place of %?
To match only one character in MySQL, you can use underscore(_) in place of %. The syntax is as follows:
SELECT *FROM yourTableName WHERE yourColumnName LIKE ‘yourString_’;
To understand the above syntax, let us create a table. The query to create a table is as follows:
mysql> create table OneCharactermatchDemo -> ( -> Id int NOT NULL AUTO_INCREMENT, -> PassoutYear year, -> PRIMARY KEY(Id) -> ); Query OK, 0 rows affected (0.76 sec)
Insert some records in the table using insert command. The query is as follows:
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2008');
Query OK, 1 row affected (0.14 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2007');
Query OK, 1 row affected (0.18 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2010');
Query OK, 1 row affected (0.10 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2011');
Query OK, 1 row affected (0.13 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2012');
Query OK, 1 row affected (0.12 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2006');
Query OK, 1 row affected (0.10 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2019');
Query OK, 1 row affected (0.14 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2016');
Query OK, 1 row affected (0.13 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2017');
Query OK, 1 row affected (0.34 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2015');
Query OK, 1 row affected (0.17 sec)
mysql> insert into OneCharactermatchDemo(PassoutYear) values('2020');
Query OK, 1 row affected (0.13 sec)Display all records from the table using select statement. The query is as follows:
mysql> select *from OneCharactermatchDemo;
The following is the output:
+----+-------------+ | Id | PassoutYear | +----+-------------+ | 1 | 2008 | | 2 | 2007 | | 3 | 2010 | | 4 | 2011 | | 5 | 2012 | | 6 | 2006 | | 7 | 2019 | | 8 | 2016 | | 9 | 2017 | | 10 | 2015 | | 11 | 2020 | +----+-------------+ 11 rows in set (0.00 sec)
Here is the query to match only one character using underscore. The query is as follows:
mysql> select *from OneCharactermatchDemo where PassoutYear Like '200_';
The following is the output:
+----+-------------+ | Id | PassoutYear | +----+-------------+ | 1 | 2008 | | 2 | 2007 | | 6 | 2006 | +----+-------------+ 3 rows in set (0.00 sec)
Updated on: 30-Jul-2019
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